Pzazz
culd any one give a logical solution 4 ths problem......why does ths have 0 roots..
Well... To avoid using ln() function, I prefer to use an XY plane analysis.
We have:
o y = 2^x
o y = x-1
That means:
o y=2^x passes by (0,1) and when x>0, it increases exponantially fast, which is very very fast

. 2^x is never negative and so remains in cadran I and II.
o y=x-1 is a line passing by (0,-1) and has a very slow increase when x increases. When x < 1, y=x-1 remains in cadran III and IV. It's only after x=1 that we have a y > 0 and that we are in cadran I.
All in all, at x=1, y=2^x is at (1,2) and y=x-1 is at (1,0). After that, as y=2^x increases much faster than y=x-1, this 2 graphs will never intersect one another.