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Jabjagotabhisavera
Bunuel
How many squares with sides 1/2 inch long are needed to cover a rectangle that is 4 feet long and 6 feet wide? (1 foot = 12 inches)

(A) 24
(B) 96
(C) 3,456
(D) 13,824
(E) 14,266

Hi Bunuel,

As per my understanding, length is always greater than width.

Is it OK to say length is 4ft and width is 6ft? This implies that width is greater than length.

You are right length > width. Edited.
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Bunuel
How many squares with sides 1/2 inch long are needed to cover a rectangle that is 6 feet long and 4 feet wide? (1 foot = 12 inches)

(A) 24
(B) 96
(C) 3,456
(D) 13,824
(E) 14,266

Total area = 24 ft^2 converted to inches = 3456 inch^2

Area of square is 1/4 inches

Thus you can hold 3456*4 squares or 13,824 squares
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Step one

Convert the units

1 foot = 12 inches
6 feet = 6 * 12 = 132 inches
4feet = 4 * 12 = 48 inches

Step two

Create the rectangle

W = \(48/(1/2)= 96\)
L = \(132/(1/2)= 264\)

Third step

Just multiply the units digits

6*4 = 24 ... 13,824

(A) 24 ... discard ---> too small
(B) 96
(C) 3,456
(D) 13,824
(E) 14,266

D
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Hello from the GMAT Club BumpBot!

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