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How many times will the digit 7 be written when listing the integers f
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Updated on: 29 Oct 2014, 08:43
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How many times will the digit 7 be written when listing the integers from 1 to 1000? A. 110 B. 111 C. 271 D. 300 E. 304 OPEN DISCUSSION OF THIS QUESTION IS HERE: howmanytimeswillthedigit7bewritten99914.html
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Originally posted by noboru on 31 Jul 2009, 09:35.
Last edited by Bunuel on 29 Oct 2014, 08:43, edited 2 times in total.
Renamed the topic, edited the question and added the OA.



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Re: How many times will the digit 7 be written when listing the integers f
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31 Jul 2009, 12:41
noboru wrote: How many times will the digit 7 be written when listing the integers from 1 to 1000?
110 111 271 300 304 answer is 300 from 1 100 , 7 occurs 20 times, similary for all other 100s except 701  800 & number 700. on calculating it, it comes to 300 times, please post if there is anyother easy way to calculate this



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Re: How many times will the digit 7 be written when listing the integers f
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Updated on: 17 Jun 2012, 17:39
[EDIT  REMOVED BY USER]
Originally posted by nplaneta on 31 Jul 2009, 12:58.
Last edited by nplaneta on 17 Jun 2012, 17:39, edited 1 time in total.



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Re: How many times will the digit 7 be written when listing the integers f
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31 Jul 2009, 19:13
Take all the number as 3 digits ( 001 to 999) i fill the units place with 7 , i can fill the ten and hundreds place in 10 ways 10 * 10 * 1 = 100
Same way for hundreds = 10 * 1 * 10 = 100 thousands = 1* 10* 10 = 100
So totally 300 ways



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Re: How many times will the digit 7 be written when listing the integers f
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01 Aug 2009, 06:36
can it be 270 if v do in how mny digits 7 will not be used it will be 9*9*9 =729 so 1000729 =271 wot im missing help???



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Re: How many times will the digit 7 be written when listing the integers f
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01 Aug 2009, 06:45
can it be 270 if v do in how mny digits 7 will not be used it will be 9*9*9 =729 so 1000729 =271 wot im missing help???



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Re: How many times will the digit 7 be written when listing the integers f
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05 Dec 2009, 20:25
300, 777 is counted three times when it should be only once. However, 777 has three 7's so it offsets its reappearance. Here is how I did it: Single digit: 1 (7); 2 Digits: 9+10=19; 3 Digits: 7 as the unit digit: 9*10=90 7 as the middle digit: 9*10=90 7 as the leading digit: 19*10 ( no restriction on 0 since it is not leading the number)  2 because 777 is counted in all three scenarios. +2 because 777 has three 7's. Awesome question though.
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Re: How many times will the digit 7 be written when listing the integers f
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08 Jul 2010, 23:51
how did you get 9*10 for 3 digits??



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Re: How many times will the digit 7 be written when listing the integers f
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09 Jul 2010, 00:47
Answer is 300. From 1 to 100, total 7 digits will be 10 + 1 +9 = 20 From 1 to 1000 to 20 * 10 = 200 and 100 7 digits for 700 to 799 Total = 200 + 100 = 300
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Re: How many times will the digit 7 be written when listing the integers f
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03 Aug 2011, 00:23
My method is not as simple, but I think it is easier to understand than the previous methods.
First off for single and double digit numbers, lets assume everyone can figure out that there are 20 7's.
Once we get into the hundreds, we know that the 700s will be tricky, but for all the other hundreds, we should be seeing 20 7's in each set of hundred. Other than the 700s, there are only 8 other sets of hundreds (100s, 200s, 300s, etc.). So we multiply 20 * 8 = 160...bringing the total to 180.
So far we have accounted for all the 7's for single and double digit numbers and all hundreds not including the 700s.
For the 700s, we already know that there is at least one 7 from the numbers 700799. So there's 100 right there. At this point the only remaining numbers with 7 are the same ones we identified for single and double digit numbers. (20 of em)
So in the end we have... 20+160+100+20 = 300
compared to the above methods, this is a very crude way of doing this problem



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Re: How many times will the digit 7 be written when listing the integers f
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29 Oct 2014, 08:44
noboru wrote: How many times will the digit 7 be written when listing the integers from 1 to 1000?
A. 110 B. 111 C. 271 D. 300 E. 304
Consider numbers from 0 to 999 written as follows: 1. 000 2. 001 3. 002 4. 003 ... ... ... 1000. 999 We have 1000 numbers. We used 3 digits per number, hence used total of 3*1000=3000 digits. Now, why should ANY digit have preferences over another? We used each of 10 digits equal # of times, thus we used each digit (including 7) 3000/10=300 times. Answer: D. OPEN DISCUSSION OF THIS QUESTION IS HERE: howmanytimeswillthedigit7bewritten99914.html
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Re: How many times will the digit 7 be written when listing the integers f
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29 Oct 2014, 08:45
Bunuel wrote: noboru wrote: How many times will the digit 7 be written when listing the integers from 1 to 1000?
A. 110 B. 111 C. 271 D. 300 E. 304
Consider numbers from 0 to 999 written as follows: 1. 000 2. 001 3. 002 4. 003 ... ... ... 1000. 999 We have 1000 numbers. We used 3 digits per number, hence used total of 3*1000=3000 digits. Now, why should ANY digit have preferences over another? We used each of 10 digits equal # of times, thus we used each digit (including 7) 3000/10=300 times. Answer: D. OPEN DISCUSSION OF THIS QUESTION IS HERE: howmanytimeswillthedigit7bewritten99914.htmlAnother approach: In the range 0100: 7 as units digit  10 times (7, 17, 27, ..., 97); 7 as tens digit  10 time (71, 72, 73, ..., 79); So in first one hundred numbers 7 is written 10+10=20 times. In 10 hundreds 7 as units or tens digit will be written 10*20=200 times. Plus 100 times when 7 is written as hundreds digit (700, 701, 702, ..., 799). Total 200+100=300. Answer: D.
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Re: How many times will the digit 7 be written when listing the integers f
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