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Bunuel
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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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Imo the fastest way to find duplicates is to just mentally add combos of 2 numbers. Since only 2 numbers are combined, it's quickly apparent that only 1 and 33 will create a duplicate.
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Asked: How many unique sums can be created by adding 2 distinct numbers from the set {1, 2, 4, 8, 16, 32, 33}?

1. 3 = 2 + 1
2. 5 = 4 + 1
3. 6 = 4 + 2
4. 9 = 8 + 1
5. 10 = 8 + 2
6. 12 = 8 + 4
7. 17 = 16 + 1
8. 18 = 16 + 2
9. 20  = 16 + 4
10. 24 = 16 + 8
11. 33 = 32 + 1
12. 34 = 32 + 2 = 33 + 1
13. 36 = 32 + 4 
14. 40 = 32 + 8
15. 48 = 32 + 16
16. 35 = 33 + 2 
17. 37 = 33 + 4
18. 41 = 33 + 8
19. 49 = 33 + 16
20. 65 = 33 + 32

IMO D

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satvikd22
Is there a more optimized way rather than calculating each one. I did 7C2 but couldn't figure out how to find duplicates for each combo in an easy way.
­Chose 2 from 7 numbers we have a sum. 7C2 = 21
Since we have 01 duplicate here: 1 + 31 = 32 + 2
-> Unique sum = 21 - 1 = 20
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­You can write this numbers in a binary form, so:
\(2^0, 2^1, 2^2, 2^3, 2^4, 2^5, 2^5+1\)­­­­­­­

With the binary numbers we can write all the numbers doing combination of them, only changing the first 0 or 1. Like:

\(1\times2^0+0\times2^1+0\times2^2\times2^3+0\times2^4+1\times2^5 = 33\)­­­­­­­

Even 33, so we can take off 33 and do a combination \(6\choose3\)­.

And we will find 20, that is the final answer.

Kudos!!­­­­­
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