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# How would you approach this problem? Thanks in advance

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Intern
Joined: 22 Jul 2008
Posts: 10

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04 Aug 2008, 21:24
How would you approach this problem? Thanks in advance.

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Joined: 29 Aug 2007
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04 Aug 2008, 22:04
flygmat wrote:
How would you approach this problem? Thanks in advance.

"Is (x-y)/(x+y) > 1" doesnot mean that "is -y > y?".
it would be if both (x-y) and (x+y) were +ve. since we do not know, it could be or not.

1: if x > y, y is -ve, and x > lyl, then (x-y)/(x+y) > 1. if x > y, y is also +ve, then no. so nsf.

2: If x is +ve and x > lyl, then yes (x-y)/(x+y) > 1. If x is +ve but < lyl, then no. so nsf.

togather: also nsf cuz we have both conditions applied above.

so E.

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Re: GMATPREP - inequality   [#permalink] 04 Aug 2008, 22:04
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# How would you approach this problem? Thanks in advance

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