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05 Jan 2004, 10:23
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This week, I'm going to sit back on this one.
This week, I'm going to sit back on this one.
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05 Jan 2004, 10:39
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Lets call the colors R O Y G B V
Opposite R, we can have O Y G B V
For each case, there are 3 ways to configure the remainder.
For example, if R is opposite O, than we can have Y opposite G, Y opposite B, or Y opposite V.
5*3 is 15.
So I'm certain that the answer is a multiple of fifteen, but I don't know why 30 or 60 would be correct.
I doubt they made a mistake, but I'm a bit befuddled.
Opposite R, we can have O Y G B V
For each case, there are 3 ways to configure the remainder.
For example, if R is opposite O, than we can have Y opposite G, Y opposite B, or Y opposite V.
5*3 is 15.
So I'm certain that the answer is a multiple of fifteen, but I don't know why 30 or 60 would be correct.
I doubt they made a mistake, but I'm a bit befuddled.
05 Jan 2004, 10:48
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To add to my last post, I would think that the configuration of opposite sides can be the only "variant" (for lack of a better word), since any two cubes with opposite sides configured the same way can be reoriented to look alike...
