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jimmyjamesdonkey
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I am going somewhere with this... (a + b)/(a b) < 0 28 May 2008, 18:15
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I am going somewhere with this...

(a + b)/(a – b) < 0



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gmatnub
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I am going somewhere with this... (a + b)/(a b) < 0 28 May 2008, 18:33
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A DS problem?

2 possible conditions

(a + b) < (a – b)

OR

(a + b) > (a – b)
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jimmyjamesdonkey
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I am going somewhere with this... (a + b)/(a b) < 0 28 May 2008, 18:36
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Yes, part of a DS problem...gmatnub, how did you simplify that???

Normally I would cross multiply to simplify, but since we have a zero wouldn't we get...


(a + b) < 0

OR

(a + b) > 0


?????
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gmatnub
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I am going somewhere with this... (a + b)/(a b) < 0 28 May 2008, 18:41
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Less than zero is NOT zero
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jimmyjamesdonkey
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I am going somewhere with this... (a + b)/(a b) < 0 28 May 2008, 18:48
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Ahhhh, but still how would you simplify??? Would you still cross multiply somehow?
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I am going somewhere with this... (a + b)/(a b) < 0 28 May 2008, 18:52
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When you work with inequalities, when you multiply or divide by a NEGATIVE number, you switch sign. Since you don't know whether the value of the denominator (a-b) is positive or negative, you have 2 conditions.


2 possible conditions

(a + b) < (a – b) ---> b < -b

OR

(a + b) > (a – b) ----> b > -b
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I am going somewhere with this... (a + b)/(a b) < 0 28 May 2008, 18:54
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thanks....i need this spelled at for me...inequalities in my weak spot.
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I am going somewhere with this... (a + b)/(a b) < 0 28 May 2008, 19:02
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What if I change the question to...

(a + b)/(a – b) < 1...

Would you be able to simplify this anymore?



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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