I don't have the OA to this question

Question

Is x-y+1 greater than x+y-1?

(1) x>0
(2) y<0

I don't have the OA to this problem. Would someone please tell me the OA so that I can satisfy my curiosity?
I'll highly appreciate it.
Thanks

durgesh79 · Answer

Q Is x-y+1 > x+y-1
Is 2y < 2
Is y < 1

Statement 1 : not suff 
Statement 2 : suff .... anything less than 0 is less than 1 also

Should be B.

tarek99 · Answer

yeah, I got B as well, but was wondering if anyone has the OA to this problem. but good to know that someone else also got B. Would anyone have the OA to this problem?

spriya · Answer

Consider (1) : x>0 now it does not indicate whether y is +ve or -ve hence say y=3,x=3=> x-y+1 > x+y-1 is false now say ,y=-1,x=1 => x-y+1 > x+y-1 is true => insufficient (2) : y<0 => x can be >0 or <0 => x-y+1 > x+y-1 is true always since here x is increased by some value in LHS when y is -ve and RHS is decreased by some value ,even if x is -ve or positive its value is shifted along number line LHS>RHS always => sufficient IMO B

nishchals · Answer

how about this - write the problem as 
 is x -(y-1) > x+ (y-1) ?
if 2 is given, y-1 is always negative hence (2) is enough

I don't have the OA to this question

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