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I don't have the OA to this question

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SVP
SVP
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Joined: 21 Jul 2006
Posts: 1512

Kudos [?]: 1008 [0], given: 1

I don't have the OA to this question [#permalink]

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New post 02 Aug 2008, 05:37
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is x-y+1 greater than x+y-1?

(1) x>0
(2) y<0





I don't have the OA to this problem. Would someone please tell me the OA so that I can satisfy my curiosity?
I'll highly appreciate it.
Thanks

Kudos [?]: 1008 [0], given: 1

Director
Director
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Joined: 27 May 2008
Posts: 541

Kudos [?]: 363 [0], given: 0

Re: I don't have the OA to this question [#permalink]

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New post 02 Aug 2008, 05:59
tarek99 wrote:
Is x-y+1 greater than x+y-1?

(1) x>0
(2) y<0

I don't have the OA to this problem. Would someone please tell me the OA so that I can satisfy my curiosity?
I'll highly appreciate it.
Thanks


Q Is x-y+1 > x+y-1
Is 2y < 2
Is y < 1

Statement 1 : not suff
Statement 2 : suff .... anything less than 0 is less than 1 also

Should be B.

Kudos [?]: 363 [0], given: 0

SVP
SVP
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Joined: 21 Jul 2006
Posts: 1512

Kudos [?]: 1008 [0], given: 1

Re: I don't have the OA to this question [#permalink]

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New post 02 Aug 2008, 07:38
yeah, I got B as well, but was wondering if anyone has the OA to this problem. but good to know that someone else also got B. Would anyone have the OA to this problem?

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VP
VP
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Joined: 17 Jun 2008
Posts: 1374

Kudos [?]: 406 [0], given: 0

Re: I don't have the OA to this question [#permalink]

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New post 02 Aug 2008, 22:55
tarek99 wrote:
Is x-y+1 greater than x+y-1?

(1) x>0
(2) y<0





I don't have the OA to this problem. Would someone please tell me the OA so that I can satisfy my curiosity?
I'll highly appreciate it.
Thanks


Consider (1) : x>0
now it does not indicate whether y is +ve or -ve hence say y=3,x=3=> x-y+1 > x+y-1 is false
now say ,y=-1,x=1 => x-y+1 > x+y-1 is true => insufficient

(2) : y<0 => x can be >0 or <0 => x-y+1 > x+y-1 is true always
since here x is increased by some value in LHS when y is -ve and RHS is decreased by some value ,even if x is -ve or positive its value
is shifted along number line LHS>RHS always => sufficient

IMO B
_________________

cheers
Its Now Or Never

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Intern
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Joined: 02 Aug 2008
Posts: 29

Kudos [?]: 2 [0], given: 0

Re: I don't have the OA to this question [#permalink]

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New post 03 Aug 2008, 02:34
how about this - write the problem as
is x -(y-1) > x+ (y-1) ?
if 2 is given, y-1 is always negative hence (2) is enough

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Re: I don't have the OA to this question   [#permalink] 03 Aug 2008, 02:34
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