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Fig
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I found this problem on the internet while trying to find 26 Oct 2007, 15:31
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KillerSquirrel
Fig
KillerSquirrel
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To me :)

o p(2 bad apples) = 15*14 / (30*29) = 7/29
o p(2 bad oranges) = 6*5 / (30*29) = 1/29

Then,
o P(2 bad orange & 2 bad apples) = p(2 bad apples) * p(2 bad oranges) = 7/29 * 1/29 = 7/(29)^2

Yes - perfect as always - the answer should be 7/(29^2)

:)

Thanks :)... U are not that bad too ;).... Did u fix a date for your test? :)

[I know... I asked u it one time already... Perhaps, this time I will have answer :wink: :wink: ... Never giving up ! :wink: ]

My test will be ~ December

:)
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Uhmmmm.... It was starting well... but finally, it's not yet this time... Let see next time ;)

No matter the date... U better come back with the good news here ;)
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KillerSquirrel
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I found this problem on the internet while trying to find 26 Oct 2007, 15:51
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Fig
KillerSquirrel
Fig
KillerSquirrel
Fig
To me :)

o p(2 bad apples) = 15*14 / (30*29) = 7/29
o p(2 bad oranges) = 6*5 / (30*29) = 1/29

Then,
o P(2 bad orange & 2 bad apples) = p(2 bad apples) * p(2 bad oranges) = 7/29 * 1/29 = 7/(29)^2

Yes - perfect as always - the answer should be 7/(29^2)

:)

Thanks :)... U are not that bad too ;).... Did u fix a date for your test? :)

[I know... I asked u it one time already... Perhaps, this time I will have answer :wink: :wink: ... Never giving up ! :wink: ]

My test will be ~ December

:)

Uhmmmm.... It was starting well... but finally, it's not yet this time... Let see next time ;)

No matter the date... U better come back with the good news here ;)
Show more


I don't have a specific date - I keep pushing it back until I will feel ready

:(
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Fig
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I found this problem on the internet while trying to find 26 Oct 2007, 23:07
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KillerSquirrel
Fig
KillerSquirrel
Fig
KillerSquirrel
Fig
To me :)

o p(2 bad apples) = 15*14 / (30*29) = 7/29
o p(2 bad oranges) = 6*5 / (30*29) = 1/29

Then,
o P(2 bad orange & 2 bad apples) = p(2 bad apples) * p(2 bad oranges) = 7/29 * 1/29 = 7/(29)^2

Yes - perfect as always - the answer should be 7/(29^2)

:)

Thanks :)... U are not that bad too ;).... Did u fix a date for your test? :)

[I know... I asked u it one time already... Perhaps, this time I will have answer :wink: :wink: ... Never giving up ! :wink: ]

My test will be ~ December

:)

Uhmmmm.... It was starting well... but finally, it's not yet this time... Let see next time ;)

No matter the date... U better come back with the good news here ;)

I don't have a specific date - I keep pushing it back until I will feel ready

:(
Show more


I see... Well, it should be very very soon if it's not yet the case :)
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singh_amit19
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I found this problem on the internet while trying to find 27 Oct 2007, 02:11
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nitinneha
I found this problem on the internet while trying to find some practice material:

Tom has 30 apples, 15 of them are bad.Steve has 30 oranges and 6 of them are bad. Both Tom and Steve have to put two apples and two oranges in a basket at random. What is the probability that the basket would have exactly two bad apples and two bad oranges?

I tried to solve it but looks like something is missing..........can someone help.
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I think....probab shud be: (15C2/30C2) X (6C2/30C2)
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ywilfred
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I found this problem on the internet while trying to find 29 Oct 2007, 19:08
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30 apples --> 15 bad, 15 good
30 oranges --> 6 bad, 24 good

P1 = P(bad apple) AND P(bad apple) = 15/30 * 14/29 = 7/29
P2 = P(bad orange) AND P(bad orange) = 6/30 * 5/29 = 1/29

P = P1 AND P2 = 7/29 * 1/29 = 7/841



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