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12 Nov 2024, 03:49
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Blue: 40
Total: 100
The probability of drawing a red ball from a bag containing only red and blue balls is 0.2 higher than the probability of drawing a blue ball.
Select for Blue the number of blue balls that could be in the bag, and select for Total the total number of balls that could be in the bag that would be jointly consistent with the given information. Make only two selections, one in each column.
Select for Blue the number of blue balls that could be in the bag, and select for Total the total number of balls that could be in the bag that would be jointly consistent with the given information. Make only two selections, one in each column.
| Blue | Total | |
| 10 | ||
| 40 | ||
| 50 | ||
| 60 | ||
| 100 |
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Official Answer
Blue: 40
Total: 100
12 Nov 2024, 03:49
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Official Solution:
We are given that P(red) = P(blue) + 0.2. Since there are only red and blue balls in the bag, we also have P(red) + P(blue) = 1.
Solving this system of equations gives P(blue) = 0.4 and P(red) = 0.6. This implies that the ratio of blue balls to the total number of balls is 4:10.
From the available options, only 40 for blue and 100 for the total maintains this ratio.
Correct answer:
Blue "40"
Total "100"
Bunuel
We are given that P(red) = P(blue) + 0.2. Since there are only red and blue balls in the bag, we also have P(red) + P(blue) = 1.
Solving this system of equations gives P(blue) = 0.4 and P(red) = 0.6. This implies that the ratio of blue balls to the total number of balls is 4:10.
From the available options, only 40 for blue and 100 for the total maintains this ratio.
Correct answer:
Blue "40"
Total "100"
03 Feb 2025, 02:41
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I have revised the question, solution, and formatting by adding more details to enhance clarity.
