Official Solution: Bunuel
Alice and Bob are on an escalator with 80 steps from bottom to top. The escalator moves upward at a constant rate of \(s\) steps per second.
Alice starts from the bottom and walks upward at a constant rate of 2 steps per second relative to the escalator. Bob starts from the top and walks downward at a constant rate of 3 steps per second relative to the escalator.
Bob takes four times as long to reach the bottom as Alice takes to reach the top.
Select for
t the time in seconds after which Alice and Bob meet, and select for
n the number of steps Alice would have walked on the escalator by the time she reaches the top. Make only two selections, one in each column.
Given: • Escalator length = 80 steps
• Escalator moves upward at \(s\) steps/sec
• Alice walks upward at 2 steps/sec
relative to the escalator, so her
net speed is \(2 + s\)
• Bob walks downward at 3 steps/sec
relative to the escalator, so his
net speed is \(3 - s\)
• Bob takes 4 times as long to reach the bottom as Alice takes to reach the top
Step 1: Find \(t\), the time when Alice and Bob meet Alice and Bob’s relative speed \(= (2 + s) + (3 - s) = 5\) steps/sec. So, they will meet in \(t =\) distance / relative speed = 80/5 = 16 seconds.
Step 2: Use the time condition to find \(s\) Since Bob takes four times as long to reach the bottom as Alice takes to reach the top, then:
\(4 * \frac{80}{2 + s} = \frac{80}{3 - s}\)
\(s = 2\)
Step 3: Find \(n\), the number of steps Alice walks on the escalator Alice’s total time to reach the top \(= \frac{80}{2 + 2} = 20\) seconds. She walks at 2 steps/sec on the escalator, so, \(n = 2 * 20 = 40\) steps
Correct answer: \(t\)
"16"\(n\)
"40"