Official Solution: Bunuel
At a mountain observatory, astronomers set exposure times for two types of targets. Each faint target requires R seconds per image, and each bright target requires a shorter exposure of S seconds per image. On Night 1, the team captured 35 images using a total of 625 seconds. On Night 2, they captured 140 images using a total of 1730 seconds. On both nights, both faint and bright targets were captured.
Select for
R and
S values for R and S that are jointly consistent with the information provided. Make only two selections, one in each column.
Night 1 average = 625/35 ≈ 17.9
Night 2 average = 1730/140 ≈ 12.4
So S must be below both averages and R must be above both. Since R > S, that narrows to R = 19 or 21, and S = 10, 12, or 14.
Night 1 equation is xR + (35 - x)S = 625, where x is the number of faint images on Night 1.
First test R = 19. Substituting gives 19x + S(35 - x) = 625. For S = 10, 12, or 14, this does not give an integer solution for x, so R cannot be 19.
Now test R = 21. Substituting gives 21x + S(35 - x) = 625.
For S = 10, this gives x = 25, which is an integer solution.
For S = 12 or 14, no integer solution exists.
Therefore the only consistent pair is
R = 21 and
S = 10.
Correct answer: R
"21"S
"10"