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13 Jan 2026, 12:47
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Distance: 12
Intensity: 2
A point light source shines equally in all directions. The light intensity measured at a sensor is inversely proportional to the square of the distance from the source.
When the distance is 6 meters, the intensity is 8 units.
Select for Distance a distance in meters and select for Intensity an intensity in units that would be jointly consistent with the given information. Make only two selections, one in each column.
When the distance is 6 meters, the intensity is 8 units.
Select for Distance a distance in meters and select for Intensity an intensity in units that would be jointly consistent with the given information. Make only two selections, one in each column.
| Distance | Intensity | |
| 2 | ||
| 4 | ||
| 12 | ||
| 16 | ||
| 24 | ||
| 32 |
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Official Answer
Distance: 12
Intensity: 2
13 Jan 2026, 12:47
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Official Solution:
We are given that the intensity is inversely proportional to the square of distance, so Intensity = k/Distance^2, where k is a constant.
Since when D = 6 meters, I = 8 units, we have 8 = k/6^2, which gives k = 288.
Now check the options to find a pair (D, I) such that I = 288/D^2. Only (12, 2) fits.
Thus, Distance = 12 meters and Intensity = 2 units.
Correct answer:
Distance "12"
Intensity "2"
Bunuel
We are given that the intensity is inversely proportional to the square of distance, so Intensity = k/Distance^2, where k is a constant.
Since when D = 6 meters, I = 8 units, we have 8 = k/6^2, which gives k = 288.
Now check the options to find a pair (D, I) such that I = 288/D^2. Only (12, 2) fits.
Thus, Distance = 12 meters and Intensity = 2 units.
Correct answer:
Distance "12"
Intensity "2"
