Official Solution: Bunuel
A driver is choosing between two pricing plans for evening parking in a downtown garage.
• Plan A charges a one time entry fee that covers the first 2 hours, plus $\(x\) for each additional hour or fraction of an hour beyond the first 2 hours.
• Plan B charges no entry fee, but charges $\(\frac{3x}{2}\) for the first hour and $\(\frac{3x}{2}\) for each additional hour or fraction of an hour beyond the first hour.
Select for
Plan A entry fee and for
Plan B total charge the two figures, in US dollars ($), that could be Plan A's entry fee and Plan B’s total charge for 3 hours and 20 minutes such that both plans would charge the same total amount. Make only two selections, one in each column.
Plan A: The entry fee covers the first 2 hours. Time beyond 2 hours is 1 hour 20 minutes, which is billed as 2 additional hours.
So Plan A total = \(F + 2x\), where \(F\) is the entry fee.
Plan B: For 3 hours 20 minutes, billing “per hour or fraction of an hour” means 4 billed hours total.
So Plan B total = \(4 * \frac{3x}{2} = 6x\).
Set totals equal: \(F + 2x = 6x\)
\(F = 4x\)
Then Plan B total = \(6x = 1.5F\).
From the options, the only pair where the second is 1.5 times the first is:
\(F = 8\) and
Plan B total = \(6x = 1.5F = 12\).
Correct answer: Plan A entry fee
"8"Plan B total charge
"12"