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If 10^a*10^b*10^c = 1,000,000, and a, b, and c are different positive

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Math Expert
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Joined: 02 Sep 2009
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If 10^a*10^b*10^c = 1,000,000, and a, b, and c are different positive  [#permalink]

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New post 17 Oct 2018, 02:43
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

89% (01:14) correct 11% (00:54) wrong based on 53 sessions

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Senior Manager
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Joined: 09 Jun 2014
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Location: India
Concentration: General Management, Operations
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Re: If 10^a*10^b*10^c = 1,000,000, and a, b, and c are different positive  [#permalink]

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New post 17 Oct 2018, 02:52
Bunuel wrote:
If \(10^a*10^b*10^c = 1,000,000\), and a, b, and c are different positive integers, then \(10^a + 10^b + 10^c =\)


A. 1011

B. 1100

C. 1101

D. 1110

E. 1111



Looks simple ..here is my approach..

10^(a+b+c)=10^6

So (a+b+c)=6

Now its give a,b,c are different positive integers..

So they can 1,2,3 (any of a,b,c which doesnt matter for our final value since base is 10)

So assume a=1,b=2,c=3

Now 10^a + 10^b +10^c= 10+100+1000 =1110

So my answer would be D here.



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Re: If 10^a*10^b*10^c = 1,000,000, and a, b, and c are different positive   [#permalink] 17 Oct 2018, 02:52
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