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# If 2^(2p - 10) = 2*2^(9 - 2p), then p =

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Math Expert
Joined: 02 Sep 2009
Posts: 51280
If 2^(2p - 10) = 2*2^(9 - 2p), then p =  [#permalink]

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03 Aug 2018, 03:51
00:00

Difficulty:

5% (low)

Question Stats:

81% (00:46) correct 19% (01:09) wrong based on 36 sessions

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If $$2^{(2p - 10)} = 2*2^{(9 - 2p)}$$, then p =

A. 5
B. 3
C. 0
D. -1
E. -2

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Posts: 676
Location: India
Concentration: Operations, Marketing
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Re: If 2^(2p - 10) = 2*2^(9 - 2p), then p =  [#permalink]

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03 Aug 2018, 03:54
2^(2p - 10) = 2*2^(9 - 2p)
2^(2p - 10) = 2^(1+9 - 2p)
2^(2p - 10) = 2^(10 - 2p)
2p - 10 = 10 - 2p
4p = 20
p = 5

Hence, A.
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Joined: 31 Oct 2013
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If 2^(2p - 10) = 2*2^(9 - 2p), then p =  [#permalink]

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Updated on: 04 Aug 2018, 12:36
Bunuel wrote:
If $$2^{(2p - 10)} = 2*2^{(9 - 2p)}$$, then p =

A. 5
B. 3
C. 0
D. -1
E. -2

$$2^{(2p - 10)} = 2*2^{(9 - 2p)}$$

$$2^{(2p-10)} = 2^{(1 + 9-2p)}$$

2p - 10 = 1 + 9 - 2p

4p = 20

p = 5

The best answer is A.

Originally posted by selim on 04 Aug 2018, 01:38.
Last edited by selim on 04 Aug 2018, 12:36, edited 1 time in total.
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Re: If 2^(2p - 10) = 2*2^(9 - 2p), then p =  [#permalink]

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04 Aug 2018, 06:59
Bunuel wrote:
If $$2^{(2p - 10)} = 2*2^{(9 - 2p)}$$, then p =

A. 5
B. 3
C. 0
D. -1
E. -2

$$2p - 10 = 9 - 2p +1$$

Or, $$4p = 20$$

Thus, p = 5 , Answer must be (A) 5
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Re: If 2^(2p - 10) = 2*2^(9 - 2p), then p = &nbs [#permalink] 04 Aug 2018, 06:59
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# If 2^(2p - 10) = 2*2^(9 - 2p), then p =

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