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If 2^5, 3^3, and 13^2 are all factors of the product of 936 and w wher

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V
Joined: 02 Sep 2009
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If 2^5, 3^3, and 13^2 are all factors of the product of 936 and w wher  [#permalink]

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New post 25 Apr 2016, 02:54
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A
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E

Difficulty:

  25% (medium)

Question Stats:

79% (01:58) correct 21% (01:57) wrong based on 130 sessions

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If 2^5, 3^3, and 13^2 are all factors of the product of 936 and w where w is a positive integer, what is the smallest possible value of w?

A. 26
B. 39
C. 42
D. 65
E. 156

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Re: If 2^5, 3^3, and 13^2 are all factors of the product of 936 and w wher  [#permalink]

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New post 25 Apr 2016, 05:11
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Re: If 2^5, 3^3, and 13^2 are all factors of the product of 936 and w wher  [#permalink]

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New post 28 Apr 2016, 04:01
stonecold wrote:
Here 156 has three two's
two three's
and one 13
rest of them must be in w
so w= 13*3*4 = 156

Smash E


E) is the right answer, but don't you mean 936 in the first sentence?

936= 2^3 *3^2 *13^1

So what you need is 2 more 2's, 1 more 3 and 1 more 13.
This gives us 2^2 *3 *13=156 E)
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Re: If 2^5, 3^3, and 13^2 are all factors of the product of 936 and w wher  [#permalink]

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New post 28 Apr 2016, 10:33
PhilSad92 wrote:
stonecold wrote:
Here 156 has three two's
two three's
and one 13
rest of them must be in w
so w= 13*3*4 = 156

Smash E


E) is the right answer, but don't you mean 936 in the first sentence?

936= 2^3 *3^2 *13^1

So what you need is 2 more 2's, 1 more 3 and 1 more 13.
This gives us 2^2 *3 *13=156 E)


Yup definitely its a TYPO

\(936\)= \(2^3\)x \(3^2\)x \(13^1\)
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Re: If 2^5, 3^3, and 13^2 are all factors of the product of 936 and w wher  [#permalink]

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New post 12 Dec 2017, 11:28
2^5, 3^3, and 13^2 are all factors of the product of 936 and w
936=2^33^213
So, we left with 2^2*3*13=156
Hence answer is E
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Re: If 2^5, 3^3, and 13^2 are all factors of the product of 936 and w wher &nbs [#permalink] 12 Dec 2017, 11:28
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If 2^5, 3^3, and 13^2 are all factors of the product of 936 and w wher

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