Last visit was: 19 Nov 2025, 15:01 It is currently 19 Nov 2025, 15:01
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
vikramjit_01
Joined: 02 Jan 2007
Last visit: 22 Aug 2009
Posts: 162
Own Kudos:
Posts: 162
Kudos: 40
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
KillerSquirrel
Joined: 08 Jun 2005
Last visit: 28 Mar 2009
Posts: 520
Own Kudos:
Posts: 520
Kudos: 634
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Himalayan
Joined: 26 Feb 2006
Last visit: 09 Aug 2011
Posts: 384
Own Kudos:
Posts: 384
Kudos: 627
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Himalayan
Joined: 26 Feb 2006
Last visit: 09 Aug 2011
Posts: 384
Own Kudos:
Posts: 384
Kudos: 627
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Himalayan
vikramjit_01
If 2 different representatives are to be selected at random from a group of 10 employees and if p is the probability that both representatives selected will be women, is p > 1/2?

(1) More than 1/2 of the 10 employees are women.
(2) The probability that both representatives selected will be men is less than 1/10.

Stay tuned for the OA :wink:

10c2 = 45

we need total 23 pairs of women to have p>1/2
to have 23 pair, we need 8 women.

from 1:
if w = 6, 6c2 = 15, p = 15/45 <1> 1/2

so nsf.

from 2:
if p < 1/10 for both men, no of pair of both men is less than 4.5. since 4.5 pair can not be possible therefore it must be 4 or 3 or 2 or 1. what ever be the pair, no of men can not be more than 3 because if no of men is 4, then the pair of both men becomes 6, which is not possible.. therefore the no of men is 3 or less than 3.

if n (men) = 3......p (both women) <1> 1/2

so still not suff.....

togather is also nsf.


this is not what i have posted. i tried reposting what i did but it is not posting what exactly i wrote.

10c2 = 45

we need total 23 pairs of women to have p > 1/2
to have 23 pair, we need 8 women.

from 1:

if w = 6, 6c2 = 15, p = 15/45 is less 1/2
if w = 7, 7c2 = 21, p = 21/45 is less 1/2
if w = 8, 8c2 = 28, p = 28/45 is grater 1/2

so nsf.

from 2:
if p < 1/10 for both men, no of pair of both men is less than 4.5. since 4.5 pair can not be possible therefore it must be 4 or 3 or 2 or 1. what ever be the pair, no of men can not be more than 3 because if no of men is 4, then the pair of both men becomes 6, which is not possible.. therefore the no of men is 3 or less than 3.

if m = 3, w = 7, 7c2 = 21, p = 21/45 is less 1/2

if m = 2, w = 8, 8c2 = 28, p = 28/45 is grater 1/2

so still not suff.....

togather is also nsf.


EEE
User avatar
vikramjit_01
Joined: 02 Jan 2007
Last visit: 22 Aug 2009
Posts: 162
Own Kudos:
Posts: 162
Kudos: 40
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Nice work Himalayan (nice avatar too) especially with Statement II.
Both statements almost reach the same conclusion from opposite directions and so C doesn't stand a chance here.

Yes OA = E :good
User avatar
Himalayan
Joined: 26 Feb 2006
Last visit: 09 Aug 2011
Posts: 384
Own Kudos:
Posts: 384
Kudos: 627
Kudos
Add Kudos
Bookmarks
Bookmark this Post
vikramjit_01
Nice work Himalayan (nice avatar too) especially with Statement II.
Both statements almost reach the same conclusion from opposite directions and so C doesn't stand a chance here.

Yes OA = E :good


Thanks Vikramjit. my avatar is a real picture of KUMARI, a living goddes.

more about Kumari: https://en.wikipedia.org/wiki/Kumari
User avatar
vikramjit_01
Joined: 02 Jan 2007
Last visit: 22 Aug 2009
Posts: 162
Own Kudos:
Posts: 162
Kudos: 40
Kudos
Add Kudos
Bookmarks
Bookmark this Post
From that link
"The power of the Kumari is perceived to be so strong that even a glimpse of her is believed to bring good fortune"

I guess Himalayan's avatar might bring us all some good fortune :)
User avatar
Himalayan
Joined: 26 Feb 2006
Last visit: 09 Aug 2011
Posts: 384
Own Kudos:
Posts: 384
Kudos: 627
Kudos
Add Kudos
Bookmarks
Bookmark this Post
vikramjit_01
From that link
"The power of the Kumari is perceived to be so strong that even a glimpse of her is believed to bring good fortune"

I guess Himalayan's avatar might bring us all some good fortune :)



Fortunately, I had her glimpses. She is above beauty (800). :wink:



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderators:
Math Expert
105390 posts
GMAT Tutor
1924 posts