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IrinaOK
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If -2<=x<=2 and 3<=y<=8, which of the following Updated on: 01 Sep 2007, 05:56
Originally posted by IrinaOK on 31 Aug 2007, 19:06.
Last edited by IrinaOK on 01 Sep 2007, 05:56, edited 2 times in total.
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If -2<=x<=2 and 3<=y<=8, which of the following represents the range of all possible variables of y-x?

5<=y-x<=6
1<=y-x<=5
1<=y-x<=6
5<=y-x<=10
1<=y-x<=10


Apart from visualizing and drawing how else can this problem be solved?
have any idea...?



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subhen
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If -2<=x<=2 and 3<=y<=8, which of the following 31 Aug 2007, 19:22
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This should be easy. Just do what it says. Subtract the two extremes of x from y to get the extreme values for y-x.

Given that -2<=x<=2 and 3<=y<=8

Therefore 5<=(y-x)<=6
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IrinaOK
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If -2<=x<=2 and 3<=y<=8, which of the following 31 Aug 2007, 19:45
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subhen
This should be easy. Just do what it says. Subtract the two extremes of x from y to get the extreme values for y-x.

Given that -2<=x<=2 and 3<=y<=8

Therefore 5<=(y-x)<=6
Show more


That was my answer too. Though incorrect :)

you can draw line and actualy and put the given numbers on it, you will see it is not the asnwer...

but is there any other than drawing and visualising approaches?
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subhen
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If -2<=x<=2 and 3<=y<=8, which of the following 01 Sep 2007, 00:20
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Sorry I realized my silly mistake. Since this is a subtraction, we cannot just subtract lower and upper bounds of one number from the other.
In order to find extreme values for the expression. Find out the least value and the maximum value of the expression.

The least value for expression y-x occurs when y is lowest and x is highest.
i.e. 3-2=1 This is the lower bound for the expression

The max value for the expression y-x occurs when y is highest and x is lowest.
i.e. 8 - (-2) = 10 This is the upper bound for the expression

Therefore 1 <= y-x <=10
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surbab
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If -2<=x<=2 and 3<=y<=8, which of the following 01 Sep 2007, 00:28
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The answer is 1<=y-x<=10. hence E.
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Fig
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If -2<=x<=2 and 3<=y<=8, which of the following 01 Sep 2007, 01:25
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(E) for me :)

o -2<=x<=2
<=> 2 >= -x >= -2 as we multply all by -1
<=> -2<=-x<=2 (1)

o 3<=y<=8 (2)

(1) + (2) <=> 3 + (-2) <= y + (-x) <= 8 + 2
<=> 1 <= y-x <= 10
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IrinaOK
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If -2<=x<=2 and 3<=y<=8, which of the following 01 Sep 2007, 05:57
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Fig
(E) for me :)

o -2= -x >= -2 as we multply all by -1
-2 3 + (-2) 1 <= y-x <= 10
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I got it,

Thank You,guys!



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Hi there,
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