kalpeshchopada7 wrote:
I wud differ with the final answer. if jade3's solution method is agreed upon, we get 55^3/110. which is (55*55*55)/(55*2) or (55*55)/2. Thus the odd number divided by 2 will result into remainder 1.
In that case the OA should B.
The colored step cannot be used because, while finding the remainder you cannot reduce the numbers(Ex:when you divide 32/64 the remainder is 32, But if you reduce 32/64 to 1/2 you get the remainder 1)
According to remainder theory
If P be the product of N1, N2, N3…
And let D divide P, then the remainder of P/D would be same as remainder of (Mod[N1/D]*Mod[N2/D]*Mod[N3/D]*…..)/D where Mod denotes the remainder operation
In our case Remainder of (55*55*55/110)= Remainder of (3025*55/110)
Remainder of(3025/110) = 55
Remainder of(55/110)=55
Now according to the remainder theorem Remainder of (55*55*55/110)= Remainder of (55*55/110)=55