Bunuel
If 2x = 2y – 3z, what is the value of z?
(1) y = x + 2
(2) x = y – 2
First, rewrite the equation, so that we have z on one side:
2x = 2y - 3z
3z = 2y - 2x
Statement 1:y = x + 2
One way is picking numbers:
y = 4 --> x = 2 --> 3z = 2*4 - 2*2 = 4
y = -2 --> x = -4 --> 3z = 2*-2 - 2*-4 = 4
The solution of 3z will always be 4, therefore z = \(\frac{4}{3}\)
Additionally, you can solve this with Algebra:
y = x + 2
2y = 2x + 4
2y - 2x = 4
You can plug this into the stem: 3z = 2y - 2x = 4 --> z = \(\frac{4}{3}\)
SUFF
Statement 2:x = y – 2
If you realize that this is
the same as statement 1, you can be done in a few seconds.
But again, you can pick numbers:
x = 4 --> y = 6 --> 3z = 2*6 - 2*4 = 4
x = -2 --> y = 0 --> 3z = 2*0 - 2*-2 = 4
Again, 3z will always be 4, therefore z = \(\frac{4}{3}\)
The Algebra-way:
x = y - 2
2 = y - x
4 = 2y - 2x
You can plug this into the stem: 3z = 2y - 2x = 4 --> z = \(\frac{4}{3}\)
SUFF
Answer D