Bunuel
If \(\sqrt{2x-3}=x-3\), then what is the value of x ?
A. 1
B. 2
C. 3
D. 4
E. 6
Solution:Since a square root can never be negative, we see that x can’t be 1 or 2 (notice that the right hand side will be -2 and -1, respectively).
If x = 3, the left hand side is √3 while the right hand side is 0.
If x = 4, the left hand side is √5 while the right hand side is 1.
If x = 6, the left hand side is √9 = 3 and the right hand side is 3. Since both sides of the equation are 3, x = 6.
Alternate Solution:Let’s square both sides of the given equation and then solve for x:
2x - 3 = x^2 - 6x + 9
0 = x^2 - 8x + 12
0 = (x - 6)(x - 2)
We see that x can equal either 6 or 2.
Because this is a square root equation, we need to test each possible solution, in case there is an extraneous solution. We see that x = 6 works in the original equation, but x = 2 does not because we would have √(4 - 3) = 2 - 3, which would yield the false statement 1 = -1.
Answer: E