Bunuel
If \(2x − y = 10\) and \(\frac{x}{y} = 3\), then x =
A. − 10
B. 2
C. 4
D. 6
E. 12
I'd typically use the approach that
selim used.
However, another approach is to
test the answer choicesWe can also use some
number sense to help us determine which answer choices to test first.
Notice that we're told x/y = 3
So, if answer choice A were correct, we'd get -10/y = 3, in which case y is some fraction.
Now if x is an integer (-10) and y is some fraction, we can see that these values for x and y will not satisfy the other equation, 2x - y = 10
So, let's start testing answer choices (possible x-values) that yield "nicer" values of y when we solve the equation x/y = 3
Answer choice B is no good, because we get 2/y = 3, which will yield a fraction value for y.
Answer choice C is no good, because we get 4/y = 3, which will yield a fraction value for y.
Answer choice D is promising, since we get 6/y = 3, which means y = 2
Good so far!
So, x = 6 and y = 2 satisfies the equation x/y = 3, but does it satisfy the other equation, 2x - y = 10?
When we plug in those values, we get: 2(6) - 2 = 10, PERFECT!
So, x = 6 and y = 2 satisfies BOTH equations
Answer: D
Cheers,
Brent