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19 May 2004, 18:57
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If (3^4n) +1 is divided by 10, can the remainder be 0?
a) n=2m+1, m is a positive integer
b) n> 4
a) n=2m+1, m is a positive integer
b) n> 4
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19 May 2004, 20:02
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A is sufficient.
A) if n = 2m+1 and m>0 (integer)
we hev 3^(8m+4)
for 8m+4 = 14,18,22 we have the result to be mutiple of 10
but for no integer values of m we can get these numbers
hence remainder is not zero
B) if n > 0 for n=1.5 3^4n = 3^6+1 is a multiple of 10
for n = 1 3^4+1 is not a mutiple of 10
A) if n = 2m+1 and m>0 (integer)
we hev 3^(8m+4)
for 8m+4 = 14,18,22 we have the result to be mutiple of 10
but for no integer values of m we can get these numbers
hence remainder is not zero
B) if n > 0 for n=1.5 3^4n = 3^6+1 is a multiple of 10
for n = 1 3^4+1 is not a mutiple of 10
19 May 2004, 20:34
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anan
8m+4 = 12, 20, 28,... ...
Besides, in statement n> 4, so it can be re-written as [3^(4*5)] +1 = 3^20 + 1.
I still can't figure out the answer but I don't quite agree with your explanation.
8m+4 = 12, 20, 28,... ...
Besides, in statement n> 4, so it can be re-written as [3^(4*5)] +1 = 3^20 + 1.
I still can't figure out the answer but I don't quite agree with your explanation.
