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Given 3 is a factor of positive integers \(x\) and \(y\), so \(x\) and \(y\) are multiples of 3.

Stmt 1: Units digit of \(4^{x+y}\) is 6.
Focus on units digit when 4 is raised to nth power and keep multiplying units digits with base number.
4^1 = 4, 4^2 = 6, 4^3 = 4, 4^4 = 6 and so on. Basically 4 when raised to some power, it will have unit's digit = 4 if power is odd and = 6 if power is even.

So x + y = even.

Now, either both x and y are even or both x and y are odd. Nothing can be said further hence insufficient.

Stmt 2: Units digit of \(9^{xy}\) is 9

Focus on units digit when 9 is raised to nth power and keep multiplying units digits with base number.
9^1 = 9, 9^2 = 1, 9^3 = 9, 9^4 = 1 and so on. Basically 9 when raised to some power, it will have unit's digit = 9 if power is odd and = 1 if power is even.

Therefore xy has to be odd. Only case when this is possible is, both x and y are odd. Hence sufficient.

Therefore answer is B.


Bunuel
If 3 is a factor of positive integers \(x\) and \(y\), is \(x\) odd?

(1) Units digit of \(4^{x+y}\) is 6

(2) Units digit of \(9^{xy}\) is 9



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