Given 3 is a factor of positive integers \(x\) and \(y\), so \(x\) and \(y\) are multiples of 3.
Stmt 1: Units digit of \(4^{x+y}\) is 6.
Focus on units digit when 4 is raised to nth power and
keep multiplying units digits with base number. 4^1 = 4, 4^2 = 6, 4^3 = 4, 4^4 = 6 and so on. Basically 4 when raised to some power, it will have unit's digit =
4 if power is
odd and =
6 if power is
even.
So x + y = even.
Now, either both x and y are even or both x and y are odd. Nothing can be said further hence
insufficient.
Stmt 2: Units digit of \(9^{xy}\) is 9
Focus on units digit when 9 is raised to nth power and
keep multiplying units digits with base number.9^1 = 9, 9^2 = 1, 9^3 = 9, 9^4 = 1 and so on. Basically 9 when raised to some power, it will have unit's digit =
9 if power is
odd and =
1 if power is
even.
Therefore xy has to be odd. Only case when this is possible is, both x and y are odd. Hence
sufficient.
Therefore answer is B.Bunuel
If 3 is a factor of positive integers \(x\) and \(y\), is \(x\) odd?
(1) Units digit of \(4^{x+y}\) is 6
(2) Units digit of \(9^{xy}\) is 9