If 6 fair 6-sided dice are rolled, what is the probability that at lea

We can either find the probability of getting at least two of the same, or we can find the probability of getting no repeats and subtract that from one. The latter is easier, so let's do that. As soon as I decide to do a problem in a way that requires one last little step at the end that I might otherwise forget to do (we've all made that mistake, so don't pretend you've never done it!! ), I flip my computer mouse over and then get to work solving the problem. That way, when I go to click my answer, I have a little reminder to make sure I've done that last step.

What's the probability of getting SOMETHING on the first die? 1
What's the probability of getting something DIFFERENT on the second die? 5/6
What's the probability of getting something DIFFERENT on the third die? 4/6
...3/6
...2/6
...1/6

So, the probability of getting all different is \(1*\frac{5}{6}*\frac{4}{6}*\frac{3}{6}*\frac{2}{6}*\frac{1}{6}\)

\(\frac{5!}{6^5}\)

\(1-\frac{5!}{6^5}\)

Answer choice D.