Bunuel
If \(|a+1|=|b-1|\), what is the value of \(a-b\) ?
(1) \(ab>0\)
(2) \(\frac{a}{b}≠ -1\)
\(|a+1|=|b-1|\)
This eqn only holds for certain combinations of \(a\) and \(b\)
i.e. if \(a=4\) then \(b\) has to be either \(6\) or \(-4\)
So \(a-b\) can be either \(-2\) or \(8\)
If \(a=-6\) then \(b\) can be \(6\) or \(-4\)
So \(a-b=-12\) or \(-2\)
Similarly we can verify by taking other numbers too
(1) \(ab>0\)This implies \(a\) and \(b\) have to have the same sign
So if \(a\) is \(4 \) then \(b\) has to be \(6\) and \(a-b=-2 \)
If \(a=-6\) then \(b\) has to be \(-4\) and \(a-b=-2\)
(other values for a and b will give similar result)
SUFF.(2) \(\frac{a}{b}≠ -1\)Again from our pre-work we can see that we cannot have \(a=4\) and \(b=-4\) nor can we have \(a=-6\) and \(b=6\)
Thus the only other possibility is \(a=4\) and \(b=6\) or \(a=-6\) and \(b=-4 \)
Thus \(a-b=-2 \)
(other values for a and b will give similar result)
SUFF.Ans D
Hope it helps.