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If a = 2/3^7 + 2/3^8 + 2/3^9 +2^2/3^9, then what is the value of a?

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Joined: 02 Sep 2009
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If a = 2/3^7 + 2/3^8 + 2/3^9 +2^2/3^9, then what is the value of a? [#permalink]

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New post 11 Jan 2018, 21:48
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

93% (01:18) correct 7% (00:56) wrong based on 41 sessions

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Joined: 04 May 2017
Posts: 2
Re: If a = 2/3^7 + 2/3^8 + 2/3^9 +2^2/3^9, then what is the value of a? [#permalink]

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New post 12 Jan 2018, 00:52
Answer : B

a=2/3^7 + 2/3^8 + 2/3^9 + 2/3^9

a= 2/3^7 *(1+1/3+1/9+2/9)

a=2/3^7 * (15/9)

a= 30/3^9

a= 10/3^8
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Concentration: Finance, Accounting
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Re: If a = 2/3^7 + 2/3^8 + 2/3^9 +2^2/3^9, then what is the value of a? [#permalink]

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New post 12 Jan 2018, 05:32
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a= \(\frac{2}{3^7}\)+\(\frac{2}{3^8}\)+\(\frac{2}{3^9}\)+\(\frac{2^2}{3^9}\)

= \(\frac{2}{3^7}\)[1+\(\frac{1}{3}\)+\(\frac{1}{9}\)+\(\frac{2}{9}\)]

= \(\frac{2}{3^7}\)*[\(\frac{15}{9}\)]

= \(\frac{30}{3^9}\)

= \(\frac{10}{3^8}\)

Answer: B.
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Re: If a = 2/3^7 + 2/3^8 + 2/3^9 +2^2/3^9, then what is the value of a?   [#permalink] 12 Jan 2018, 05:32
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