Bunuel
If a = 2,879 + b, what is the value of the digit b?
(1) a is divisible by 7.
(2) a is divisible by 2.
Given a = 2,879 + b
We have range of 'b' from -9 to 9 since 'b' is a digit.
So, 'a' ranges from 2879-9 to 2879+9, i.e, 2870 to 2889.
Question stem: b=?
st1:-a is divisible by 7
So a=2870,2877, and 2884 when b=-9, -2, and 5 respectively.
Since b has more than one values, hence insufficient.
st2:-a is divisible by 2
So a=2870,2872, .......,2884,2886,2888 when b=-9, -7,.......,5,7,9 respectively.
Since b has more than one values, hence insufficient.
Now, combining st1 and st2, we have
a=2870 and 2884 when b=-9 and 5 respectively.
Since b has more than one values, hence insufficient.
Hence, insufficient.
Ans. (E)
I thought in decimal system we consider digits to be {0 to 9}. If they are considered negative as well, then good job on the solution. E is the right answer.