Hi everyone,
My first contribution to this forum and the first of many to come. There it goes:
The first step would be squaring the first equation so we can get both equations with similar terms to the power of 4:
\((a^2+b^2)^2=(15)^2\)
\(a^4+2(ab)^2+b^4=225\)
Now we should organize the terms, thus we move \(a^4+b^4\) to the left of the equation:
\(a^4+b^4=225-2(ab)^2\)
Therefore, we have a system of two equations with similar terms:
\(a^4+b^4=225-2(ab)^2\)
\(a^4+b^4=153\)
We would resolve it as follows:
\(225-2(ab)^2=153\)
\(2(ab)^2=72\)
\((ab)^2=36\)
\(ab=\pm6\)
Here we get two possible values for a*b, 6 and -6. Since the question asks us for the least possible value of a*b, then the answer is -6.
Therefore,
the correct answer is A. To all of you reading this answer, if you notice that I made a mistake, please, feel free to correct me.
Hope it helps!