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Number of fav outcomes/ total outcomes

fav outcomes: 11-20 i.e 10 on each dice
total outcomes: 20 for each throw
so
10/20 *10/20 = 1/2*1/2 =1/4

IMO C
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If a 20-sided die, numbered with consecutive integers from 1 - 20, is rolled twice,

As we are rolling 20 side die twice => Number of cases = \(20*20\) = 400

What is the probability of getting a number greater than ten on each roll?

P(Getting a number more than 10)
= P(Getting any number from 11 to 20) = 10 cases out of 20

P(Getting more than 10 on each roll) = \(\frac{10*10}{400}\) = \(\frac{1}{4}\)

So, Answer will be C
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

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