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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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Bunuel
If \(a=3^3*2^9\), \(b= 3^6 *7^3\), \(c = 2^6*5^3\), which of the following is true?


A. \(c>b>a\)

B. \(b>a>c\)

C. \(a>c>b\)

D. \(b>c>a\)

E. \(c>a>b\)

Compare these two things:

\(3^6 *7^3\) vs. \(2^6*5^3\)

They both have something-to-the-power-of-six times something-to-the-power-of-three.
The thing on the left has a larger base value for each.
The thing on the left is obviously larger. Cool, b>c. A, C, and E are out.

We don't need to compare a to b since both remaining answer choices have b>a.

All that's left is to find whether a>c or c>a.

\(3^3*2^9\) vs. \(5^3*2^6\)

Get rid of \(2^6\)

\(3^3*2^3\) vs. \(5^3\)

\(27*8\) vs. \(125\)

The first one is clearly larger. a>c. D is out.

Answer choice B.
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Here is my solution
IT is clear that B is the biggest. This can help us elimiate all answer choices except B & D which gives us a 50/50
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Bunuel
If \(a=3^3*2^9\), \(b= 3^6 *7^3\), \(c = 2^6*5^3\), which of the following is true?

A. \(c>b>a\)
B. \(b>a>c\)
C. \(a>c>b\)
D. \(b>c>a\)
E. \(c>a>b\)

a = 3^3 × 2^9
b = 3^6 × 7^3
c = 2^6 × 5^3

If we raise each of the above positive numbers to the power of 1/3, the order of the resulting numbers will correspond to the order of the original numbers.

a^(1/3) = (3^3 × 2^9)^(1/3) = 3 × 2^3 = 24
b^(1/3) = (3^6 × 7^3)^(1/3) = 3^2 × 7 = 63
c^(1/3) = (2^6 × 5^3)^(1/3) = 2^2 × 5 = 20

Since b^(1/3) > a^(1/3) > c^(1/3), we have:

b > a > c

Answer: B
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Encountered this in LBS' free mock and their explanation is a good concept in Exponent comparative questions - Reduce the expressions to either the same power or same base.


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