Bunuel
If a and b are integers and a is odd, is b even?
(1) \((a^3 + 1)*b\) is even.
(2) \(\frac{a^2}{b} = b - 4\)
Some important rules:
#1. ODD +/- ODD = EVEN
#2. ODD +/- EVEN = ODD
#3. EVEN +/- EVEN = EVEN
#4. (ODD)(ODD) = ODD
#5. (ODD)(EVEN) = EVEN
#6. (EVEN)(EVEN) = EVEN Given: a and b are integers and a is odd Target question: Is b even? Statement 1: \((a^3 + 1)b\) is even. If a is ODD, then a³ is ODD, which means
a³ + 1 is EVEN.
So, we can rewrite statement 1 as: (
EVEN)(b) = EVEN
We can see that if
b is ODD, the product will be even, and if
b is EVEN the product will still be even.
Since we can’t answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: \(\frac{a^2}{b} = b - 4\)Multiply both sides of the equation by b to get:
a² = b(b - 4)Expand: to get:
a² = b² - 4bAdd 4b to both sides:
a² + 4b = b²If a is ODD, then a² is ODD
Since 4 is even, we know that 4b is EVEN
So our equation becomes:
ODD + EVEN = b²Since odd + even = odd, our equation becomes:
ODD = b² This means we can be certain that b is ODD, which means the answer to the target question is
NO, b is definitely not even.Since we can answer the
target question with certainty, statement 2 is SUFFICIENT
Answer: B
Cheers,
Brent