DH99
If a and b are nonzero numbers, Is a-b>0?
Statement 1: |a|-b>0
Statement 2: a-|b|>0
Bunuel: Can you please help solve this question.I don't have OA.
Re-arrange the equation in the question stem by adding b to both sides and we notice that the question is really asking:
Is a > b?
Also note that both a and b cannot be 0:
S1:
Re-arrange the equation by adding b to both sides and we get:
|a| > b
Note that the abs value hides the sign of a. We can test a few numbers that both meets the criteria |a| > b :
If a = -3 and b = 2 a < b
If a = 3 and b = 2 then a > b
Therefore, it is not sufficient.
S2:
Re-arrage the equation by adding |b| to both sides and we get:
a > |b|
Note that |b| hides the sign of b, but since a > |b| that means a must be positive since absolute value of a number is always positive and b cannot be 0
if b is negative: a > b since a is positive and a positive is always > a negative
if b is positive, a > b since we are given that a > |b|
Therefore, the answer is B