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If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4, the [#permalink]
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Updated on: 13 May 2017, 05:56
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If \(\frac{a}{b} = \frac{1}{3}\), \(\frac{b}{c} = 2\), \(\frac{c}{d} = \frac{1}{2}\), \(\frac{d}{e} = 3\) and \(\frac{e}{f} = \frac{1}{4}\), then what is the value of \(\frac{abc}{def}\) ? (A) 27/4 (B) 27/8 (C) 3/4 (D) 3/8 (E) 1/4
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Originally posted by gmatacequants on 23 May 2014, 12:38.
Last edited by Bunuel on 13 May 2017, 05:56, edited 2 times in total.
Edited the question and added the OA.



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Re: If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4, the [#permalink]
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23 May 2014, 12:48



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Re: If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4, the [#permalink]
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24 May 2014, 01:36
gmatacequants wrote: If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4, then what is the value of abc/def ?
(A) 27/4 (B) 27/8 (C) 3/4 (D) 3/8 (E) 1/4 Solving the equation: As a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4 then, a/b*b/c*c/d = \frac{a}{d} = (1/3)*2*(1/2) = 1/3 b/c*c/d*d/e = \frac{b}{e}= 2*(1/2)*3 = 3 c/d*d/e*e/f = \frac{c}{f} = (1/2)*3*(1/4) = 3/8 (a/d)*(b/e)*(c/f) = a*b*c/(d*e*f )= (1/3)*3*(3/8) = 3/8 Hence Kudo me if you are getting help from my posts " Kudos is the best form of appreciation "Try the following problem : 10straightlinesnotwoofwhichareparallelandnothree171525.html



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Re: If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4, the [#permalink]
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24 May 2014, 06:05
gmatacequants wrote: If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4, then what is the value of abc/def ?
(A) 27/4 (B) 27/8 (C) 3/4 (D) 3/8 (E) 1/4 Let us say that a = 4 then b = 12, c = 6, d = 12, e = 4, f = 16 then abc = (4)(12)(6) and def = (12) (4) (16) (abc)/(def) = 6/16 = 3/8
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Re: If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4, the [#permalink]
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17 Jul 2014, 00:16
\(\frac{a}{b} = \frac{1}{3}, \frac{b}{c} = 2, \frac{c}{d} = \frac{1}{2}, \frac{d}{e} = 3 and \frac{e}{f} = \frac{1}{4}\) Multiple all with each other: \(\frac{abcde}{bcdef} = \frac{1*2*3*1}{3*2*4}\) \(\frac{a}{f} = \frac{1}{4}\) ............ (1) \(\frac{b}{c} * \frac{c}{d} = 2*\frac{1}{2}\) \(\frac{b}{d} = 2\) .......... (2) \(\frac{c}{d} * \frac{d}{e} = \frac{1}{2} * 3\) \(\frac{c}{e} = \frac{3}{2}\) .............. (3) Mulitply (1) (2) & (3) \(\frac{abc}{def} = \frac{1}{4} * 2 * \frac{3}{2} = \frac{3}{8}\) Answer = D
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Re: If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4, the [#permalink]
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14 Nov 2016, 09:36
Answer:D Best thing to do is to pick up a number. If not we can minimize abc/def to be fraction of just 2 variables. 1 Starting with def. We know that d=3e and f=4e ⇒ def=12e^3 2 As long as the denominator is formed of e, we need d in the numerator as long as d/e=3 is a constant. For abc, we have c=d/2, b=2c=d, a=b/3=d/3 ⇒ abc=(d^3)/6. Finally, abc/def= ((d^3)/6) / 12e^3 = (d/e)^3 x (1/(6x12)) = 3^3/6x12 = 3/8



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Re: If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4, the [#permalink]
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14 Nov 2016, 10:02
gmatacequants wrote: If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4, then what is the value of abc/def ?
(A) 27/4 (B) 27/8 (C) 3/4 (D) 3/8 (E) 1/4 Attachment:
Capture.PNG [ 4.08 KiB  Viewed 12248 times ]
So, \(\frac{abc}{def} = \frac{2*6*3}{6*2*8} = \frac{3}{8}\) Hence, answer will be (D) \(\frac{3}{8}\)
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If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4, the [#permalink]
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10 Jan 2018, 09:23
gmatacequants wrote: If \(\frac{a}{b} = \frac{1}{3}\), \(\frac{b}{c} = 2\), \(\frac{c}{d} = \frac{1}{2}\), \(\frac{d}{e} = 3\) and \(\frac{e}{f} = \frac{1}{4}\), then what is the value of \(\frac{abc}{def}\) ?
(A) 27/4 (B) 27/8 (C) 3/4 (D) 3/8 (E) 1/4 Assign some values to the given variables. Given: a/b = 1/3 Let a = 2 and b = 6 Given: b/c = 2 Since b = 6, it must be the case that c = 3 Given: c/d = 1/2 Since c = 3 , it must be the case that d = 6 Given: d/e=3 Since d = 6 , it must be the case that e = 2 Given: e/f = 1/4 Since e = 2 , it must be the case that f = 8 So, abc/def = ( 2)( 6)( 3)/( 6)( 2)( 8) = 36/96 = 3/8 Answer: A
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If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/4, the
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10 Jan 2018, 09:23






