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If a, b, and c are different integers, is (a − b)^c > 0 ?

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Math Expert
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V
Joined: 02 Sep 2009
Posts: 42631

Kudos [?]: 135880 [0], given: 12715

If a, b, and c are different integers, is (a − b)^c > 0 ? [#permalink]

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New post 28 Nov 2017, 22:29
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

49% (01:02) correct 51% (01:23) wrong based on 39 sessions

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Kudos [?]: 135880 [0], given: 12715

Senior Manager
Senior Manager
User avatar
G
Joined: 09 Mar 2017
Posts: 258

Kudos [?]: 93 [0], given: 468

Location: India
Concentration: Marketing, Organizational Behavior
WE: Information Technology (Computer Software)
If a, b, and c are different integers, is (a − b)^c > 0 ? [#permalink]

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New post 28 Nov 2017, 23:52
1
This post was
BOOKMARKED
imo D

question basically asks is \((a − b)^c\) positive?
1)b<a means (a-b) is positive
=> positive number to the power of c (irrespective of sign of c) is positive
example: \(2^(-2)\) = 0.25
S, \((a − b)^c\) is positive
sufficient

2) c = even
(a − b)^c [/m] is positive irrespective of the sign of (a-b)
example: \(-3^(-2)\)= 9
sufficient

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Kudos [?]: 93 [0], given: 468

If a, b, and c are different integers, is (a − b)^c > 0 ?   [#permalink] 28 Nov 2017, 23:52
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If a, b, and c are different integers, is (a − b)^c > 0 ?

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