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# If a, b, and c are different integers, is (a − b)^c > 0 ?

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Math Expert
Joined: 02 Sep 2009
Posts: 44413
If a, b, and c are different integers, is (a − b)^c > 0 ? [#permalink]

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28 Nov 2017, 23:29
00:00

Difficulty:

55% (hard)

Question Stats:

52% (00:58) correct 48% (01:09) wrong based on 54 sessions

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If a, b, and c are different integers, is (a − b)^c > 0 ?

(1) b < a
(2) c = 2a
[Reveal] Spoiler: OA

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Senior Manager
Joined: 09 Mar 2017
Posts: 356
Location: India
Concentration: Marketing, Organizational Behavior
WE: Information Technology (Computer Software)
If a, b, and c are different integers, is (a − b)^c > 0 ? [#permalink]

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29 Nov 2017, 00:52
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imo D

question basically asks is $$(a − b)^c$$ positive?
1)b<a means (a-b) is positive
=> positive number to the power of c (irrespective of sign of c) is positive
example: $$2^(-2)$$ = 0.25
S, $$(a − b)^c$$ is positive
sufficient

2) c = even
(a − b)^c [/m] is positive irrespective of the sign of (a-b)
example: $$-3^(-2)$$= 9
sufficient

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If a, b, and c are different integers, is (a − b)^c > 0 ?   [#permalink] 29 Nov 2017, 00:52
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# If a, b, and c are different integers, is (a − b)^c > 0 ?

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