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07 Apr 2019, 21:33
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A
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Difficulty:
65%
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Question Stats:
62% (02:24) correct
38%
(02:29)
wrong
based on 177
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If a, b, and c are three different numbers and \(\frac{x}{b-c}=\frac{y}{c-a}=\frac{z}{a-b}\), then what is the value of \(ax + by + cz\) ?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
07 Apr 2019, 22:14
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In ax+by+cz, substituting y(b-c)/(c-a) for x and y(a-b)/(c-a) for z,
solving gives us 0/c-a
Answer A
Posted from my mobile device
solving gives us 0/c-a
Answer A
Posted from my mobile device
07 Apr 2019, 22:28
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From given equation we know that a, b, c can't be equal so, Let a=1,b=2,c=3,
Then the given equation will become x=-y/2=z
Now put all the values of a, b, c in ax+by+cz
=x+2y+3z
Now as x=-y/2=z
The equation will become
=-y/2+2y-3y/2
=0
Posted from my mobile device
Then the given equation will become x=-y/2=z
Now put all the values of a, b, c in ax+by+cz
=x+2y+3z
Now as x=-y/2=z
The equation will become
=-y/2+2y-3y/2
=0
Posted from my mobile device
