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30 Jul 2022, 17:15
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
31% (01:52) correct
69%
(02:32)
wrong
based on 70
sessions
History
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Time
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Not Attempted Yet
If a, b, c and d are distinct numbers, can b be the average of a, b, c and d?
(1) a + c = 2d
(2) b + d = 2c
(1) a + c = 2d
(2) b + d = 2c
12 Aug 2022, 08:15
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Bunuel
Question is asking whether:
\(\frac{a+b+c+d}{4} =b ...(i)\)
Is \(a+c+d=3b\)...(ii)
\((1) a + c = 2d\)
Putting the value of statement 1 into equation (ii) we get:
Is \(3d =3b \), Is \(3d-3b = 0 \), Is \(3(d-b)= 0 \) we know \(d \neq b \) as it is given that all are distinct.
Hence we can answer this with a definite NO.
SUFF.
\((2) b + d = 2c\)
Putting statement (2) value in eqn. (i) we want to know:
Is \({a+3c} =4b \)
We can see that we can easily find unique integers that can both satisfy and unsatisfy the above equation.
e.g.
If \(a=5 \) , \(c=1\) , \(b=2 \) then \(d=0\) and answer is Yes
If \(a=5 \) , \(c=2\) , \(b=3 \) then \(d=1\) and answer is No
INSUFF.
Ans A
Hope it's clear.
04 Nov 2023, 04:55
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