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If A, B, C, D, and E are points in a plane such that line CD bisects

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If A, B, C, D, and E are points in a plane such that line CD bisects  [#permalink]

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New post 09 Oct 2018, 21:41
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A
B
C
D
E

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(N/A)

Question Stats:

61% (02:08) correct 39% (02:28) wrong based on 32 sessions

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If A, B, C, D, and E are points in a plane such that line CD bisects  [#permalink]

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New post 10 Oct 2018, 11:02
1
Bunuel wrote:
If A, B, C, D, and E are points in a plane such that line CD bisects ∠ACB and line CB bisects right angle ∠ACE, then ∠DCE =

(A) 22.5°
(B) 45°
(C) 57.5°
(D) 67.5°
(E) 72.5°


Angle ACE = 90 degree since CB bisects ACE then

BCE = 45 degree

ACB = 45 degree. Since CD bisects ACB

We get two angles ACD = 45/2 = 22.5 and DCB = 45/2 = 22.5

DCE = DCB + BCE = 22.5 + 45 = 67.5

Answer choice D
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Re: If A, B, C, D, and E are points in a plane such that line CD bisects  [#permalink]

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New post 10 Oct 2018, 22:11
Salsanousi wrote:
Bunuel wrote:
If A, B, C, D, and E are points in a plane such that line CD bisects ∠ACB and line CB bisects right angle ∠ACE, then ∠DCE =

(A) 22.5°
(B) 45°
(C) 57.5°
(D) 67.5°
(E) 72.5°


Angle ACE = 90 degree since CB bisects ACE then

BCE = 45 degree

ACB = 45 degree. Since CD bisects ACB

We get two angles ACD = 45/2 = 22.5 and DCB = 45/2 = 22.5

DCE = DCB + BCE = 22.5 + 45 = 67.5

Answer choice D


Great Image!! That is a perfect explanation.
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Re: If A, B, C, D, and E are points in a plane such that line CD bisects   [#permalink] 10 Oct 2018, 22:11
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