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Re: If a ≤ b ≤ c ≤ d ≤ e ≤ 110 and the average (arithmetic mean) of a, b, [#permalink]
Expert Reply

Solution



Given:
    • a ≤ b ≤ c ≤ d ≤ e ≤ 110
    • Average of a, b, c, d, and e is 100

To find:
    • The least possible value of a

Approach and Working:
As the average of all 5 elements is 100, we can say
    • Sum of all 5 = 100 * 5 = 500

As the sum of all 5 is constant, if we are trying to find the minimum possible value of one element, we need to maximise the values of every other element

From the given relation a ≤ b ≤ c ≤ d ≤ e ≤ 110, we can say
    • The maximum possible value of each of b, c, d, and e = 110
    • Therefore, the least possible value of a = 500 – (110 * 4) = 500 – 440 = 60

Hence, the correct answer is option D.

Answer: D
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If a ≤ b ≤ c ≤ d ≤ e ≤ 110 and the average (arithmetic mean) of a, b, [#permalink]
Bunuel wrote:
If a ≤ b ≤ c ≤ d ≤ e ≤ 110 and the average (arithmetic mean) of a, b, c, d, and e is 100, what is the least possible value of a?

A) 0

B) 20

C) 40

D) 60

E) 80



To make a least , we must make other integers largest.

Total = average * number of units = 100*5 = 500
maximum value of b+c+d+e = 110*4 = 440

a = (a+b+c+d+e ) - (b+c+d+e) = 500 - 440 = 60

Thus , the best answer is D.
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Re: If a b c d e 110 and the average (arithmetic mean) of a, b, [#permalink]
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Re: If a b c d e 110 and the average (arithmetic mean) of a, b, [#permalink]
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