Events & Promotions
| Last visit was: 06 Sep 2026, 11:37 |
It is currently 06 Sep 2026, 11:37 |
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 0712:01 AM PDT
-11:59 PM PDT
On the 7th, GMAT Club Tests will be Free! Including all the Quizzes, Questions, and Tests. 12 AM - 11:59 PM PDT- Sep 07
10:00 AM PDT
-11:00 AM PDT
A complete walkthrough of GMAT Club’s free 12-week GMAT study plan: what you study each week, how progress and goals are tracked, how the error log works, and how your practice unlocks paid tools at no cost. 
Sep 0201:00 PM EDT
-11:59 PM EDT
Take 30% off all study plans with code COURSEWORK - Expires on Monday 9/7
Sep 0410:00 AM EDT
-11:59 PM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.
Sep 0609:30 AM EDT
-12:30 PM EST
Top scores are possible when you enroll in a powerful EA course, taught live online + 6 months access to TTP OnDemand video courses included! Perfect class schedule and easy course access for working professionals. Class starts Sundays Sept. 6, 2026.- Sep 09
07:00 AM PDT
-10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway - Sep 09
10:00 AM PDT
-11:00 AM PDT
Three MBA applications. Three rejections. No interview invites. A year later, Aman was admitted to Cambridge Judge, SMU, and IMD. In this episode of MBA Admit Stories, Aman shares how he rebuilt his MBA application... 
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2108:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
26 Dec 2019, 02:21
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (01:53) correct
12%
(02:14)
wrong
based on 126
sessions
History
Date
Time
Result
Not Attempted Yet
If a:b is 2:3, b:c is 4:5 and c:d is 6:7, find the ratio of a:b:c:d
A. 2 : 3 : 4 : 5
B. 4 : 5 : 6 : 7
C. 2 : 3 : 6 : 7
D. 2 : 12 : 30 : 7
E. 16 : 24 : 30 : 35
A. 2 : 3 : 4 : 5
B. 4 : 5 : 6 : 7
C. 2 : 3 : 6 : 7
D. 2 : 12 : 30 : 7
E. 16 : 24 : 30 : 35
26 Dec 2019, 03:36
Kudos
Bookmarks
The standard approach in a question on bridging ratios is to find a common element to bridge two ratios.
For example, to bridge a:b and b:c and get a:b:c, ‘b’ is the common element. We make the common element equal so that we can bridge the ratios; this can be done by taking the LCM of the ‘b’ values in both the ratios. This principle holds true whenever you are bridging ratios.
a:b = 2:3 and b:c = 4:5. The LCM of 3 and 4 is 12; hence we multiply the first ratio by 4 and the second by 3 so that ‘b’ becomes the same on both. So, a:b = 8:12 and b:c = 12:15. Now that ‘b’ is common, we can bridge the ratios.
a:b:c = 8:12:15.
Now, to obtain a:b:c:d, we bridge a:b:c with c:d, keeping ‘c’ as the common element. LCM of 15 and 6 is 30; multiply a:b:c by 2 and c:d by 5 to get c=30 on both, then bridge both.
a:b:c = 16:24:30 and c:d = 30:35. Bridging, a:b:c:d = 16:24:30:35.
The correct answer option is E.
An alternative approach would be take actual numbers which are in the respective ratios, identify the common multiples and then bridge the ratio. However, under a time constraint, this may cause errors and hence, I’d recommend the method that we just used to solve this question.
Hope that helps!
For example, to bridge a:b and b:c and get a:b:c, ‘b’ is the common element. We make the common element equal so that we can bridge the ratios; this can be done by taking the LCM of the ‘b’ values in both the ratios. This principle holds true whenever you are bridging ratios.
a:b = 2:3 and b:c = 4:5. The LCM of 3 and 4 is 12; hence we multiply the first ratio by 4 and the second by 3 so that ‘b’ becomes the same on both. So, a:b = 8:12 and b:c = 12:15. Now that ‘b’ is common, we can bridge the ratios.
a:b:c = 8:12:15.
Now, to obtain a:b:c:d, we bridge a:b:c with c:d, keeping ‘c’ as the common element. LCM of 15 and 6 is 30; multiply a:b:c by 2 and c:d by 5 to get c=30 on both, then bridge both.
a:b:c = 16:24:30 and c:d = 30:35. Bridging, a:b:c:d = 16:24:30:35.
The correct answer option is E.
An alternative approach would be take actual numbers which are in the respective ratios, identify the common multiples and then bridge the ratio. However, under a time constraint, this may cause errors and hence, I’d recommend the method that we just used to solve this question.
Hope that helps!
26 Dec 2019, 04:54
Kudos
Bookmarks
Bunuel
solve in parts
a:b:c:d
2:3:
:4:5
8:12:15
:6:7
48:72:90:105
or say
16 : 24 : 30 : 35
IMO E
26 Dec 2019, 08:48
Kudos
Bookmarks
If a:b is 2:3, b:c is 4:5 and c:d is 6:7, find the ratio of a:b:c:d
A. 2 : 3 : 4 : 5
B. 4 : 5 : 6 : 7
C. 2 : 3 : 6 : 7
D. 2 : 12 : 30 : 7
E. 16 : 24 : 30 : 35 --> correct
Solution:
a/b = 2/3, b/c = 4/5 & c/d = 6/7
=> a= 2b/3, b = 4c/5 & c = 6d/7 ---(i)
=> b = 4c/5 = (4/5)(6d/7) ---(ii) from (i)
=>a = 2b/3=(2/3)(4/5)(6d/7)---(iii) from (ii)
a:b:c:d = (2/3)(4/5)(6d/7):(4/5)(6d/7): 6d/7 : d = (2*4*6)/(3*5*7): (4*6)/(5*7):6/7:1=(2*4*6*2)/(3*5*7): (4*6)/(5*7):6/7:1
=> a:b:c:d = 2*4*2: (4*6)*(5*7)/(5*7):6*(5*7)/7:1*5*7---multiply by 5*7
=> a:b:c:d = 16: 24:30:35
A. 2 : 3 : 4 : 5
B. 4 : 5 : 6 : 7
C. 2 : 3 : 6 : 7
D. 2 : 12 : 30 : 7
E. 16 : 24 : 30 : 35 --> correct
Solution:
a/b = 2/3, b/c = 4/5 & c/d = 6/7
=> a= 2b/3, b = 4c/5 & c = 6d/7 ---(i)
=> b = 4c/5 = (4/5)(6d/7) ---(ii) from (i)
=>a = 2b/3=(2/3)(4/5)(6d/7)---(iii) from (ii)
a:b:c:d = (2/3)(4/5)(6d/7):(4/5)(6d/7): 6d/7 : d = (2*4*6)/(3*5*7): (4*6)/(5*7):6/7:1=(2*4*
=> a:b:c:d = 2*4*2: (4*6)*(5*7)/(5*7):6*(5*7)/7:1*5*7---multiply by 5*7
=> a:b:c:d = 16: 24:30:35
