If a fleet of m buses uses g gallons of gasoline every 2 days, how ma

Question

If a fleet of m buses uses g gallons of gasoline every 2 days, how many gallons will be needed by four buses every 5 days?

(A) 10g/m

(B) 10gm

(C) 10m/g

(D) 20g/m

(E) 5g/(4m)

TarunKumar1234 · Answer

Since, m buses for 2 days need g gallons
So, 1 bus for 2 days need g/m gallons
and, 1 bus for 1 day need g/2m gallons

further, 4 buses for 1 day need 4*g/2m= 2g/m gallons
And, 4 buses for 5 days need = 10g/m gallons.

Ans. A.

MathRevolution · Answer

'm' buses use 'g' gallons of gasoline every '2' days:

1 bus will use g/m gallons for '2' days.

=> For 1 day, the '1' bus will use  \frac{g}{2m}  gallons.

4 buses will use 4 *  \frac{g}{2m}  =  \frac{2g}{m}  gallons

For 5 days, '4' buses will use 5 *  \frac{2g}{m}  gallons =  \frac{10g}{m}

Answer A

CrackverbalGMAT · Answer

SOLUTION: We know M1D1/W1 = M2D2/W2 (M-Number of Men | D-Number of Days & W=Total work or capacity and here it is the volume of fuel) Thus m*2 / g = 4 * 5 / x => x = 10 g/m (OPTION A) Hope this helps

Devmitra Sen(Math)

imeanup · Answer

\frac{m_1 * d_1 * t_1}{w_1} = \frac{m_2 * d_2 * t_2 }{ w_2}  , where  m=men, d=day, t=time . Since  t   is not given we can cancel  t .

\frac{m*2 }{ g} = \frac{4 * 5 }{ x }

x = \frac{10 *g}{m}

Ans A

bobnil · Answer

Follow the attached file for an alternative joint variation concept & formulation that I learned during my school days from my Dad.
Accordingly, 
BUS --> gasoline --> days
 m ----> g --------> 2

4 ------> ?(let, X)--> 5

so, equitation will be : m*X*2 = 4*g*5 =>  X= 10g/m

Biswadeep20 · Answer

In 2 days, m buses use g gallons. 
In 2 days, 1 bus will use g/m gallons.
In 1 day, 1 bus will use g/2m gallons.

Now, in 1 day, 4 buses will use 4g/2m gallons.
Finally, in 5 days, 4 buses will use 20g/2m  . 
Hence, the answer is 10g/m.
A is the required answer.

Posted from my mobile device

bumpbot · Answer

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If a fleet of m buses uses g gallons of gasoline every 2 days, how ma

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If a fleet of m buses uses g gallons of gasoline every 2 days, how ma

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