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If a rectangle has an area of 81x^2 and a length of 27x, then what is

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If a rectangle has an area of 81x^2 and a length of 27x, then what is  [#permalink]

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New post 05 Feb 2018, 06:44
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A
B
C
D
E

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Question Stats:

97% (00:40) correct 3% (01:09) wrong based on 46 sessions

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Re: If a rectangle has an area of 81x^2 and a length of 27x, then what is  [#permalink]

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New post 05 Feb 2018, 08:00
1
Bunuel wrote:
If a rectangle has an area of 81x^2 and a length of 27x, then what is its width?

(A) 3x

(B) 9x

(C) 3x^2

(D) 9x^2

(E) 2128x^3


Area of the rectangle = Length*Width = \(81x^2\)

If length = \(27x\), Width = Area/Length = \(\frac{81x^2}{27x} = 3x\)

Therefore, the width of the rectangle is 3x(Option A)
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Re: If a rectangle has an area of 81x^2 and a length of 27x, then what is  [#permalink]

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New post 06 Feb 2018, 18:31
Bunuel wrote:
If a rectangle has an area of 81x^2 and a length of 27x, then what is its width?

(A) 3x

(B) 9x

(C) 3x^2

(D) 9x^2

(E) 2128x^3


Letting w = the width of the rectangle, we can create the following equation:

27x(w) = 81x^2

w = (81x^2)/27x = 3x

Answer: A
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Re: If a rectangle has an area of 81x^2 and a length of 27x, then what is &nbs [#permalink] 06 Feb 2018, 18:31
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