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# If a rectangle has an area of 81x^2 and a length of 27x, then what is

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Joined: 02 Sep 2009
Posts: 52285
If a rectangle has an area of 81x^2 and a length of 27x, then what is  [#permalink]

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05 Feb 2018, 05:44
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5% (low)

Question Stats:

97% (00:39) correct 3% (01:09) wrong based on 48 sessions

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If a rectangle has an area of 81x^2 and a length of 27x, then what is its width?

(A) 3x

(B) 9x

(C) 3x^2

(D) 9x^2

(E) 2128x^3

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Re: If a rectangle has an area of 81x^2 and a length of 27x, then what is  [#permalink]

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05 Feb 2018, 07:00
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Bunuel wrote:
If a rectangle has an area of 81x^2 and a length of 27x, then what is its width?

(A) 3x

(B) 9x

(C) 3x^2

(D) 9x^2

(E) 2128x^3

Area of the rectangle = Length*Width = $$81x^2$$

If length = $$27x$$, Width = Area/Length = $$\frac{81x^2}{27x} = 3x$$

Therefore, the width of the rectangle is 3x(Option A)
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Re: If a rectangle has an area of 81x^2 and a length of 27x, then what is  [#permalink]

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06 Feb 2018, 17:31
Bunuel wrote:
If a rectangle has an area of 81x^2 and a length of 27x, then what is its width?

(A) 3x

(B) 9x

(C) 3x^2

(D) 9x^2

(E) 2128x^3

Letting w = the width of the rectangle, we can create the following equation:

27x(w) = 81x^2

w = (81x^2)/27x = 3x

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Re: If a rectangle has an area of 81x^2 and a length of 27x, then what is &nbs [#permalink] 06 Feb 2018, 17:31
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# If a rectangle has an area of 81x^2 and a length of 27x, then what is

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