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07 Jan 2018, 23:07
Kudos
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
68% (01:16) correct
32%
(01:37)
wrong
based on 77
sessions
History
Date
Time
Result
Not Attempted Yet
If a set of 6 positive integers has an average (arithmetic mean) of 53, what percent of the integers is greater than 53?
(1) At least three of the integers are equal to 53.
(2) None of the integers are less than 53.
(1) At least three of the integers are equal to 53.
(2) None of the integers are less than 53.
10 Jan 2018, 23:29
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Bunuel
Lets say the integers are a,b,c,d,e,f. Given that a+b+c+d+e+f = 53*6 = 318.
(1) Say a=b=c=53. Now its possible that all other integers are also = 53 (since it says at least three are equal to 53, so there could be more). In that case 0% of integers will be > 53. But its possible that none of d,e,f are equal to 53. Eg, we could have d=e=52, and f=55. In this case, since only 1 integer is > 53, 16.66% of integers are greater than 53. So No unique answer can be determined. Insufficient.
(2) If none of the integers are less than 53, then to keep the average at 53 (or sum at 318) - none of the integers can be greater than 53 also. If we increase even one number from 53, we will have to decrease at least one other number from 53 so as to keep the sum constant as 318. So that means none of the integers is greater than 53. Thus answer is 0%. Sufficient.
Hence B answer
11 Sep 2025, 23:01
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