By the rule of arrangements, the number of arrangements of n distinct letters all taken together (no repetition) = n!
Since we are arranging the letters in Alphabetical order:
With A in the first place and with the remaining 4 letters the number of words formed = 1 * 4! = 24
Similarly with E, G, N we can form 24 words each.
Total words formed with A, E, G and N in the 1st place = 24 * 4 = 96.
The 97th word starts with R
RA are in order as per the alphabets
With the remaining 3 alphabets N, G and , the number of words formed = 1 * 1 * 3! = 6
These are RAEGN, RAENG, RAGEN, RAGNE, RANEG, RANGE
Therefore the rank of the word RANGE is 96 + 6 = 102
Option Cin this case, listing of the words was a feasible Option.
But if we had more letters, then a possible method is to keep counting until we have 2 letters remaining.
We know that with R and A as the 1st 2 letters in alphabetical order, we get 1 * 1 * 3! = 6 words
With R, A and E we get 2 words, R, A and G we get 2 words and with R, A and N, we get 2 words
With R, A and N the two words arranged alphabetically would be RANEG and RANGE.
Therefore RANGE is the last of the 6 words and therefore its rank is 96 + 6 = 102
Arun Kumar