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13 Jul 2018, 00:55
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
74% (01:29) correct
26%
(01:47)
wrong
based on 196
sessions
History
Date
Time
Result
Not Attempted Yet
If bc ≠ 0, and 3b + 2c = 18, then which of the following is NOT a possible value of c?
A. \(5\frac{3}{5}\)
B. \(6\)
C. \(8\frac{2}{5}\)
D. \(9\)
E. \(12\)
A. \(5\frac{3}{5}\)
B. \(6\)
C. \(8\frac{2}{5}\)
D. \(9\)
E. \(12\)
13 Jul 2018, 01:04
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Bunuel
If bc ≠ 0, and 3b + 2c = 18, then which of the following is NOT a possible value of c?
Plugging in numbers, we get
c= 9
3b + 2(9) = 18
3b + 18 = 18
3b = 0
b = 0
As per the question b cannot be 0, since bc ≠ 0
Hence, D.
13 Jul 2018, 06:36
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Bunuel
If bc ≠ 0, and 3b + 2c = 18, then which of the following is NOT a possible value of c?
A. \(5\frac{3}{5}\)
B. \(6\)
C. \(8\frac{2}{5}\)
D. \(9\)
E. \(12\)
A. \(5\frac{3}{5}\)
B. \(6\)
C. \(8\frac{2}{5}\)
D. \(9\)
E. \(12\)
We can use back solving strategy here.
Note :
bc ≠ 0
Neither b nor c is o. ******
Given,
3b + 2c = 18
3b + 2(9) = 18
3b = 0
b = 0.
Thus 9 can be the value of c.
The best answer is D.
