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29 Oct 2017, 01:46
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
77% (01:06) correct
23%
(01:13)
wrong
based on 258
sessions
History
Date
Time
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Not Attempted Yet
If both conveyer belt A and conveyer belt B are used, they can fill a hopper with coal in 1 hour. How long will it take for conveyer belt A to fill the hopper without conveyer belt B?
(1) Conveyer belt A moves twice as much coal as conveyer belt B.
(2) Conveyer belt B would take 3 hours to fill the hopper without conveyer belt A
(1) Conveyer belt A moves twice as much coal as conveyer belt B.
(2) Conveyer belt B would take 3 hours to fill the hopper without conveyer belt A
22 Jan 2018, 10:11
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(2) Conveyer belt B would take 3 hours to fill the hopper without conveyer belt A
The word "without A" = Individual Rate of B.
How many other ways it can be rephrased?
The word "without A" = Individual Rate of B.
How many other ways it can be rephrased?
22 Jan 2018, 11:05
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Bunuel
(1) Lets say belt B moves 'x' units of coal per hour, that means belt A can move '2x' units per hour. And since they are able to fill the hopper in 1 hour, that means the hopper contains = x + 2x = 3x units of coal.
Now hopper contains 3x units of coal and belt A can fill 2x units of coal per hour so time taken by belt A to fill the hopper alone will be = 3x/2x = 3/2 hours. Sufficient.
(2) Belt B can fill hopper in 3 hours alone. So it fills at the rate of 1/3. And together since they are able to fill in 1 hour, that means belt B fills at the rate of 2/3 (because then only 1/3 + 2/3 = 1). Since belt A fills at the rate of 2/3 hopper per hour, the time it will take to fill the hopper alone = 3/2 hours. Sufficient.
Hence D answer
