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# If C is the midpoint of the points A(–3, –4), and B(–5, 6), then AC =

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Joined: 02 Sep 2009
Posts: 58453
If C is the midpoint of the points A(–3, –4), and B(–5, 6), then AC =  [#permalink]

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Updated on: 22 Jul 2019, 06:42
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Difficulty:

25% (medium)

Question Stats:

78% (01:36) correct 22% (01:27) wrong based on 51 sessions

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If C is the midpoint of the points A(–3, –4), and B(–5, 6), then AC =

(A) 5
(B) $$\sqrt{26}$$
(C) $$\sqrt{61}$$
(D) 8
(E) 10

Source: Nova GMAT
Difficulty Level: 600

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Originally posted by Bunuel on 09 Apr 2019, 03:12.
Last edited by SajjadAhmad on 22 Jul 2019, 06:42, edited 1 time in total.
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Re: If C is the midpoint of the points A(–3, –4), and B(–5, 6), then AC =  [#permalink]

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09 Apr 2019, 03:17
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Bunuel wrote:
If C is the midpoint of the points A(–3, –4), and B(–5, 6), then AC =

(A) 5
(B) $$\sqrt{26}$$
(C) $$\sqrt{61}$$
(D) 8
(E) 10

pt c= (-3-5/2) , (-4+6/2) ; (-4,1)
AC ; √26
IMO B
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Re: If C is the midpoint of the points A(–3, –4), and B(–5, 6), then AC =  [#permalink]

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10 Apr 2019, 18:07
Bunuel wrote:
If C is the midpoint of the points A(–3, –4), and B(–5, 6), then AC =

(A) 5
(B) $$\sqrt{26}$$
(C) $$\sqrt{61}$$
(D) 8
(E) 10

Since the midpoint divides a segment into two segments of equal length, AC = ½ x AB.

The length of AB, by the distance formula, is

√[(-3 - (-5))^2 + (-4 - 6)^2]

√[4 + 100]

√104

2√26

Thus, AC = ½ x 2√26 = √26.

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Re: If C is the midpoint of the points A(–3, –4), and B(–5, 6), then AC =  [#permalink]

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22 Apr 2019, 19:25
Archit3110 wrote:
Bunuel wrote:
If C is the midpoint of the points A(–3, –4), and B(–5, 6), then AC =

(A) 5
(B) $$\sqrt{26}$$
(C) $$\sqrt{61}$$
(D) 8
(E) 10

pt c= (-3-5/2) , (-4+6/2) ; (-4,1)
AC ; √26
IMO B

I didn't understand how you arrived it in this method
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Joined: 18 Aug 2017
Posts: 5020
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
Re: If C is the midpoint of the points A(–3, –4), and B(–5, 6), then AC =  [#permalink]

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22 Apr 2019, 21:39
1
navingr8 wrote:
Archit3110 wrote:
Bunuel wrote:
If C is the midpoint of the points A(–3, –4), and B(–5, 6), then AC =

(A) 5
(B) $$\sqrt{26}$$
(C) $$\sqrt{61}$$
(D) 8
(E) 10

pt c= (-3-5/2) , (-4+6/2) ; (-4,1)
AC ; √26
IMO B

I didn't understand how you arrived it in this method

Two formula to use
Midpoint x1+X2/2 and y1+y2/2
Once you get C co-ordinate apply distance formula..
Or use distance formula between a&b and divide by 2 to get AC

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Re: If C is the midpoint of the points A(–3, –4), and B(–5, 6), then AC =   [#permalink] 22 Apr 2019, 21:39
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