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If candy bars that regularly sell for $0.40 each are on sale

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If candy bars that regularly sell for $0.40 each are on sale  [#permalink]

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New post Updated on: 11 Feb 2014, 07:18
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If candy bars that regularly sell for $0.40 each are on sale at two for $0.75, what is the percent reduction in the price of two such candy bars purchased at the sale price?

(A) \(2\frac{1}{2}%\)
(B) \(6\frac{1}{4}%\)
(C) \(6\frac{2}{3}%\)
(D) 8%
(E) \(12\frac{1}{2}%\)

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Originally posted by seabhi on 11 Feb 2014, 07:09.
Last edited by Bunuel on 11 Feb 2014, 07:18, edited 1 time in total.
Edited the question.
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Re: If candy bars that regularly sell for $0.40 each are on sale  [#permalink]

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New post 11 Feb 2014, 07:17
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Regular price is $0.80, sales price is $0.75.

So, 80-(80 * x%)=75
5 = 80*x%
x% = 5/80 = 1/16 = 6.25%
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Re: If candy bars that regularly sell for $0.40 each are on sale  [#permalink]

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New post 02 Apr 2018, 10:56
you can use the percent change formula to answer this question: ((New - Old) / Old) *100

New = 75
Old = 80

((75-80)/ 80)*100 = 6.25
answer B
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Re: If candy bars that regularly sell for $0.40 each are on sale  [#permalink]

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New post 03 Apr 2018, 05:49
seabhi wrote:
If candy bars that regularly sell for $0.40 each are on sale at two for $0.75, what is the percent reduction in the price of two such candy bars purchased at the sale price?

(A) \(2\frac{1}{2}%\)
(B) \(6\frac{1}{4}%\)
(C) \(6\frac{2}{3}%\)
(D) 8%
(E) \(12\frac{1}{2}%\)


Regular price of two candies =\(2 * 0.40 = $0.80\)

Discounted price of two candies = \($0.75\)

Difference = \(0.85 - 0.75 = $0.5\)

Percent reduction at sale price = \(\frac{0.5}{0.80}\)

\(= 6.25\)%

(B)
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Re: If candy bars that regularly sell for $0.40 each are on sale  [#permalink]

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New post 03 Apr 2018, 08:56
seabhi wrote:
If candy bars that regularly sell for $0.40 each are on sale at two for $0.75, what is the percent reduction in the price of two such candy bars purchased at the sale price?

(A) \(2\frac{1}{2}%\)
(B) \(6\frac{1}{4}%\)
(C) \(6\frac{2}{3}%\)
(D) 8%
(E) \(12\frac{1}{2}%\)


\(\frac{80 - 75}{80}*100\)

= \(6\frac{1}{4}%\), Answer must be (B)
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Re: If candy bars that regularly sell for $0.40 each are on sale  [#permalink]

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New post 05 Apr 2018, 17:12
seabhi wrote:
If candy bars that regularly sell for $0.40 each are on sale at two for $0.75, what is the percent reduction in the price of two such candy bars purchased at the sale price?

(A) \(2\frac{1}{2}%\)
(B) \(6\frac{1}{4}%\)
(C) \(6\frac{2}{3}%\)
(D) 8%
(E) \(12\frac{1}{2}%\)


We use the formula for percent change: (new - old)/old x 100. The regular (old) price for two candy bars is 0.8, and the sale price (new) is 0.75;thus, the percent reduction is:

(0.75 - 0.8)/0.8 x 100

(75 - 80)/80 x 100

-5/80 x 100 = -1/16 x 100 = -100/16 = -25/4 = 6 1/4 percent less

Answer: B
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Re: If candy bars that regularly sell for $0.40 each are on sale &nbs [#permalink] 05 Apr 2018, 17:12
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