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# If d=1/(2^3*5^7) is expressed as a terminating decimal, how

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Manager
Joined: 09 Sep 2004
Posts: 54
If d=1/(2^3*5^7) is expressed as a terminating decimal, how  [#permalink]

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Updated on: 17 Jun 2013, 22:47
1
12
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Difficulty:

65% (hard)

Question Stats:

55% (00:58) correct 45% (00:59) wrong based on 308 sessions

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If d=1/(2^3*5^7) is expressed as a terminating decimal, how many nonzero digits will d have?

(A) One
(B) Two
(C) Three
(D) Seven
(E) Ten

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-d-1-2-3-5-7-is-expressed-as-a-terminating-decimal-how-144440.html

Originally posted by mba4me on 12 Sep 2004, 01:40.
Last edited by Bunuel on 17 Jun 2013, 22:47, edited 1 time in total.
Edited the question.
Director
Joined: 16 Jun 2004
Posts: 850

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12 Sep 2004, 11:13
1
I can only think of the following method...may not be most efficient

Step 1: Looking at the denominator = no. of two's and 5's will get as many 10's (we have three 2's and three 5's(amonf seven 5's) , so I will rewrite it as

(1000)*5^4

=> d= 0.001*1/(5^4)

step 2: I will rewrite 1/(5^4) as = (2/10)*(2/10)*(2/10)*(2/10) => 16*(1/10000)

step 3: We now have d =0.0000016.
So, 2 non zero digits.
Director
Joined: 20 Jul 2004
Posts: 563

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12 Sep 2004, 15:49
1
d = 1 / (2^3 x 5^7)
= 1 / (1000 x 5^4)
= 10^-3 x (1/625)
= 10^-7 x (10000/625)
= 10^-7 x 16

So 2 digits
Intern
Joined: 07 Feb 2013
Posts: 12
GMAT 1: 650 Q48 V32
GMAT 2: 730 Q49 V41
WE: Engineering (Other)
Re: If d = 1/(2^3*5^7) is expressed as a terminating decimal,  [#permalink]

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17 Jun 2013, 22:09
4
Another way to do it is :

We know x^a*y^a=(X*Y)^a

given = 1/(2^3*5^7)
= Multiply and divide by 2^4
=2^4/(2^3*2^4*5^7)
=2^4/10^7
=> non zero digits are 16 => Ans B
Math Expert
Joined: 02 Sep 2009
Posts: 55266
Re: If d=1/(2^3*5^7) is expressed as a terminating decimal, how  [#permalink]

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17 Jun 2013, 22:48
12
10
If d=1/(2^3*5^7) is expressed as a terminating decimal, how many nonzero digits will d have?

(A) One
(B) Two
(C) Three
(D) Seven
(E) Ten

Given: $$d=\frac{1}{2^3*5^7}$$.

Multiply by $$\frac{2^4}{2^4}$$ --> $$d=\frac{2^4}{(2^3*5^7)*2^4}=\frac{2^4}{2^7*5^7}=\frac{2^4}{10^7}=\frac{16}{10^7}=0.0000016$$. Hence $$d$$ will have two non-zero digits, 16, when expressed as a decimal.

Answer: B.

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-d-1-2-3-5-7-is-expressed-as-a-terminating-decimal-how-144440.html
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Re: If d=1/(2^3*5^7) is expressed as a terminating decimal, how  [#permalink]

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18 Aug 2018, 12:41
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Re: If d=1/(2^3*5^7) is expressed as a terminating decimal, how   [#permalink] 18 Aug 2018, 12:41
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# If d=1/(2^3*5^7) is expressed as a terminating decimal, how

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